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3 years ago

Why is the value of a-1 always less than the value of a.

2 answers:

3 0

The - before the 1 represents it is less, so the -1 will always be less than a, since the - is before the one, and so that means the 1 is less than a.

saveliy_v [14]3 years ago

3 0

-1 means to subtract 1, therefor whatever number you pick for a you subtract 1 therefore a will always be more

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Create at least three equations where the quadratic has a vertex of (-3,-4). Explain how you would do that, please.

Helen [10]

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2 years ago

Please help!!!! I'm being timed I will give Branly

lyudmila [28]

Answer:

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Step-by-step explanation:

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3 years ago

Please help explanation if possible

poizon [28]

Step-by-step explanation:

Hi there!

The given equation is:

y = -2x + 5………………(i)

Comparing the equation with y = mx+c, we get;

m1 = -2

Also another equation of the line which passes through point (-4,2), we get;

(y-2) = m2(X+4)............(ii) { using the formula (y-y1) = m2(x-x2)}

According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;

m1*m2 = -1

-2*m2 = -1

or, m2 = 1/2.

Therefore, m2= 1/2.

Now, keeping the value of m2 in equation (ii).

(y-2) = 1/2(x+4)

y = (1/2)x + 4

Therefore, the required equation is: y = (1/2)x + 4.

Hope it helps!

3 0

2 years ago

If DE + EF = DF, and ____________, then the point E is the midpoint of .

gogolik [260]

DE=EF hope I helped with your studies :)

5 0

3 years ago

Rewrite the equation by completing the square.

Dennis_Churaev [7]

Once you complete the square, the simplified version of this equation is

(2x - 1)^2= 0

If you want to solve for x, subtract 1 and divide by 2.

x = 0.5

7 0

3 years ago