(xy+4y)/x = (3x-2)/x
(y+4y)/x = (3x-2)/x divide both side by x
5y /x = (3x-2)/x
5y= 3x-2 Mult by x both side
y= (3x-2)/5
$42,000 x .08 = $3,360 raise
$42,000 + $3,360 = $45,360 salary for the next year
probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444
According to a survey, 62% of americans go on vacation each .
two americans are chosen from a group of 100 americans.
what is the probability that one or both of the people chosen does not go on vacation each ?
62% americans go on vacation t
hen 38% americans does not go on vacation
Total group of americans is 100
out of 100 americans 62 go on vacation and 38 does not go on vacation
probability of one go on vacation and one does not go on vacation
= 0.62*0.38
=0.2356
probability none of them go on vacation
= 0.38*0.38
=0.1444
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Use PEMDAS
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)

The formula that we would use is the probability of both over the probability of the rain only.
P[Wind and Rain ] / P [Rain] = 0.35 / 0.65 = 0.538 = 54%
The answer is A.