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3 years ago

Why is the value of a-1 always less than the value of a.

2 answers:

3 0

<span>The - before the 1 represents it is less, so the -1 will always be less than a, since the - is before the one, and so that means the 1 is less than a.</span>

saveliy_v [14]3 years ago

3 0

-1 means to subtract 1, therefor whatever number you pick for a you subtract 1 therefore a will always be more

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The answer and how you got the answer

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$\frac{34}{15}$

Step-by-step explanation:

we are asked to evaluate

$4\tfrac{1}{4}$ ÷ $1\tfrac{7}{8}$

Above we are given mixed fraction which can be converted in proper fraction using formula given below

$a\tfrac{b}{c}=\frac{a \times c +b}{c}$

Hence

$4\tfrac{1}{4}=\frac{4 \times 4 +1}{4}$

$4\tfrac{1}{4}=\frac{17}{4}$

Also

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$1\tfrac{7}{8}=\frac{15}{8}$

Hence

$4\tfrac{1}{4}$ ÷ $1\tfrac{7}{8}$

can be written as

$\frac{17}{4}$ ÷ $\frac{15}{8}$

Also we know the rule for dividing fraction is as given below

$\frac{a}{b}$ ÷ $\frac{c}{d}$ = $\frac{a}{b} \times \frac{d}{c}$

Hence

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= $\frac{17 \times 2}{15}$

= $\frac{34}{15}$

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3 years ago