The answer is: 175 grams of fat are in the round.
m(ground round) = 1.33 ib.
First convert ib (pounds) to g (grams):
1 pound (lb) is equal to 453.592 grams (g).
m(ground round) = 1.33 ib · 453.592 g/ib.
m(ground round) = 603.28 g.
ω(fat) = 29% ÷ 100%.
ω(fat) = 0.29; mass percentage of fat.
m(fat) = ω(fat) · m(ground round).
m(fat) = 0.29 · 603.28 g.
m(fat) = 175 g; mass of fat.
<span> Au</span>₂(SeO₄)₃
O = -2 × 4 = -8
Se = + 6
So,
(+6 - 8) = -2
Means (SeO₄) contains -2 charge, Now multiply -2 by 3
-2 ₓ 3 = -6
Means,
Au₂ + (-6) = 0
Au₂ = +6
Or,
Au = 6 / 2
Au = +3
Result:
Au = +3
Se = +6
O = -2
Ni(CN)₂
Cyanide (CN⁻) contains -1 charge,
So,
N = -3
C = +2
Then,
Ni + (-1)₂ = 0
Ni - 2 = 0
Or,
Ni = +2
Result:
N = -3
C = +2
Ni = +2
Physical property
Have a nice day!
Mass of Magnesium bromide : 5.76 g
<h3>Further explanation</h3>
Complete question
<em>What mass of Magnesium bromide is formed when 1.00 g of magnesium reacts with 5.00 g of bromine?</em>
<em />
Reaction
<em />
<em />
mol Mg
mol Br₂
Limiting reactants : Br₂(smaller)
mol MgBr₂ = mol Br₂=0.0313
mass MgBr₂ :
1.55 g/L; 9.503 03 × 10^20 mL
<em>Part 1.
</em>
<em>Step 1</em>. Convert <em>kilograms to grams</em>.
1.55 kg × (1000 g/1 kg) = 1550 g
<em>Step 2</em>. Convert <em>cubic metres to litres</em>.
1 m^3 × (1000 L/1 m^3) = 1000 L
<em>Step 3</em>. Divide <em>grams by litres</em>
1.55 kg/1 m^3 = 1550 g/1000 L = 1.55 g/L
<em>Part 2.</em>
<em>Step 1</em>. Convert <em>cubic kilometres to cubic metres</em>
950 303 km^3 × (1000 m/1 km)^3 = 9.503 03 × 10^14 m^3
<em>Step 2</em>. Convert <em>cubic metres to litres</em>.
9.503 03 × 10^14 m^3 × (1000 L/1 m^3) = 9.503 03 × 10^17 L
<em>Step 3</em>. Convert <em>litres to millilitres</em>.
9.503 03 × 10^17 L × (1000 mL/1 mL) = 9.503 03 × 10^20 mL
