Answer:
Here's what I find.
Explanation:
a. Structure
Acebutolol is a secondary amine (basic). It forms a substituted ammonium salt when treated with hydrochloric acid.
The structure of the salt is shown below, with a red arrow pointing toward the positive charge on the N atom.
b. Solubility
The formula of acebutolol is C₁₈H₂₈N₂O₄.
The amide, acetyl, and ether groups confer little solubility to the molecule.
The alcohol and secondary amine do confer some solubility, because they can donate and accept hydrogen bonds.
However, they can each overcome the hydrophobic properties of only three to five carbons, and acebutolol has 18 of them.
The free amine would be preferentially soluble in lipid material (fats)
The protonated amine is ionic and therefore much more soluble in aqueous media (e.g., blood).
c. Marketing
The drug must be delivered to the tissues of the heart, where it blocks the effects of adrenalin. The best way to do this is through the blood, so acebutolol is marketed as the hydrochloride salt.
Answer:
Cellular division has three main functions: (1) the reproduction of an entire unicellular organism, (2) the growth and repair of tissues in multicellular animals, and (3) the formation of gametes (eggs and sperm) for sexual reproduction in multicellular animals.
D(density)=m(mass)/v(volume)
So in order to answer this we need the number of moles of oxygen and the right stoichiometry.
The balanced reaction should be 2HgO --> 2Hg + O2, therefore 2 moles of mercury are produced for every one mole of oxygen gas. Since we have the mass of O2 we can calculate the moles as moles = mass/RMM where RMM is the relative molecular mass of O2, which is 32 g/mol. Therefore the number of moles = 125/16 = 3.9 mol.
Since 2 moles of Hg are produced for every one mole of O2, the number of moles of Hg = 3.9*2 = 7.8 mol.
Answer:
B. They are stereoisomers
C. They are enantiomers
Explanation:
Let us consider all the options
A. D and L-glucose are not necessarily furanose, they can also be in free form (open chain) or as a six-membered ring (pyranose)
B. These sugars are stereoisomers as they have the same molecular formula, same bonds but with the different spacial arrangement.
C. Two structures are called enantiomers, if they are stereoisomers and are mirror images of each other and are not-superimposable. The given pair of structures satisfy these conditions
D. Epimers are diastereoisomers (same molecular formula and connectivity having a different spacial arrangement but are not mirror images and non-superimposable) with only one different stereocenter (if there are more than one). This is not the case
E. All monosaccharides (any sugar that cannot be hydrolysed to a simpler sugar) are reducing sugars. So, this option is invalid
