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4 years ago

A package contains 1.33 lb of ground round. If there’s 29% fat, how many grams of fat are in the round?

Chemistry

1 answer:

OlgaM077 [116]4 years ago

3 0

The answer is: 175 grams of fat are in the round.

m(ground round) = 1.33 ib.

First convert ib (pounds) to g (grams):

1 pound (lb) is equal to 453.592 grams (g).

m(ground round) = 1.33 ib · 453.592 g/ib.

m(ground round) = 603.28 g.

ω(fat) = 29% ÷ 100%.

ω(fat) = 0.29; mass percentage of fat.

m(fat) = ω(fat) · m(ground round).

m(fat) = 0.29 · 603.28 g.

m(fat) = 175 g; mass of fat.

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Which option is a physical property of matter?

Elan Coil [88]

Answer:

boiling point is the physial property of matter

5 0

3 years ago

Hydrogen gas can be prepared in the laboratory by a sin- gle-displacement reaction in which solid zinc reacts with hydrochloric

vodomira [7]

Answer:

941 g

Explanation:

Step 1: Write the balanced equation

Zn + 2 HCl ⇒ ZnCl₂ + H₂

Step 2: Calculate the moles corresponding to 14.5 g of H₂

The molar mass of H₂ is 1.01 g/mol.

14.5 g × 1 mol/1.01 g = 14.4 mol

Step 3: Calculate the number of moles of Zn required to form 14.4 moles of H₂

The molar ratio of Zn to H₂ is 1:1. The moles of Zn required are 1/1 × 14.4 mol = 14.4 mol.

Step 4: Calculate the mass corresponding to 14.4 moles of Zn

The molar mass of Zn is 65.38 g/mol.

14.4 mol × 65.38 g/mol = 941 g

6 0

3 years ago

Now, Johnny the pool guy must add enough Na2CO3 to get the pH back up to 7.60. How many grams of Na2CO3 does Johnny need to add

vaieri [72.5K]

Answer:

m = 3.4126 g

Explanation:

First, the question is incomplete but I already put in the comments the rest of the question.

Let's solve the first two questions, and then the actual question you are asking here to give you a better explanation of how to do it.

1) We need the volume of the pool, in this case is easy. Assuming the pool is rectangular, we use the volume of a parallelepiped which is the following:

V = h * d * w

We have the data, but first we will convert the feet to centimeter. This is because is easier to work the volume in cm³ than in feet.

So the height, width and depth of the pool in centimeter are:

h = 32 * 30.48 = 975.36 cm

w = 18 * 30.48 = 548.64 cm

d = 5.3 * 30.48 = 161.54 cm

Now the volume:

V = 975.36 * 548.64 * 161.54

V = 86,443,528.79 cm³ or 86,443,528.79 mL or 86,443.5 L

2) If the pool has a pH of 6.4, the concentration of H+ can be calculated with the following expression:

[H+] = antlog(-pH) or 10^(-pH)

Replacing we have:

[H+] = 10^(-6.4)

[H+] = 3.98x10^-7 M

3) Finally the question you are asking for.

According to the reaction:

Na2CO3 + H+ → 2Na+ + HCO3−

We can see that there is ratio of 1:1 between the H+ and the Na2CO3, so, if we have initially a concentration of 3.98x10^-7 M, the difference between the new concentration of H+ and the innitial, will give the concentration to be added to the pool to raise the pH. Then, with the molecular weight of Na2CO3 (105.98 g/mol) we can know the mass needed.

The new concentration of [H+] is:

[H+] = 10^(-7.6) = 2.58x10^-8 M

The difference of both [H+] will give concentration of Na2CO3 used:

3.98x10^-7 - 2.58x10^-8 = 3.73x10^-7 M

The moles:

moles = 3.73x10^-7 * 86,443.5 = 0.0322 moles

Finally the mass:

m = 0.0322 * 105.98

m = 3.4126 g

5 0

4 years ago

Design a concept map that shows the relationships among the following terms: volume , derived unit , mass , base unit , time , a

Svetlanka [38]

Base unit is the fundamental unit of measurement that is not mutually dependent. The seven base units are,

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Mass- kilogram

Time - second

Temperature - Kelvin

Current - Ampere

Luminous intensity - Candela

Amount of matter - mole

Derived units are derived from the seven base units. Like the area (square meters) is the square of length (meters), volume is the cube of length.

5 0

3 years ago

CH4 + 202 → CO2 + 2H2O<br> How many grams of O2 needed to react with 2 moles of CH4?

PtichkaEL [24]

<h3>Answer:</h3>

100 g O₂

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

Reading a Periodic Table

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O

[Given] 2 mol CH₄

[Solve] x g O₂

<u>Step 2: Identify Conversions</u>

[RxN] 1 mol CH₄ → 2 mol O₂

[PT] Molar Mass of O - 16.00 g/mol

Molar Mass of O₂ - 2(16.00) = 32.00 g/mol

<u>Step 3: Stoichiometry</u>

Set up conversion: $\displaystyle 2 \ mol \ CH_4(\frac{2 \ mol \ O_2}{1 \ mol \ CH_4})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})$
Multiply/Divide: $\displaystyle 128 \ g \ O_2$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

128 g O₂ ≈ 100 g O₂

3 0

3 years ago

Read 2 more answers