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Over [174]
3 years ago
7

Complete to simplify each expression 89-(4*2)×12 example

Mathematics
1 answer:
Rama09 [41]3 years ago
6 0
89-96 =-7. .......................
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What am I doing wrong
nalin [4]

Answer:

(4x/3)-3 <=y

Step-by-step explanation:

You should Plot the graph in this manner

5 0
3 years ago
Write an equation of the line with a slope of 0 and y -intercept of 5 .<br><br> y=
ruslelena [56]

Answer:

y=-5

Step-by-step explanation:

5 0
2 years ago
HELP ASAP BEING TIMED! If Triangle J K L is congruent to Triangle B C A, which statement must be true?
Vlada [557]

Answer:

Choice C

Step-by-step explanation:

This is like a matching question. Here's what I mean by this. We know Triangle BCA and Triange JKL are congruent. So, what we have to do is match the side lengths together.

So the first side of BCA matches with JKL, the second side of BCA matches with JKL, the third side of BCA matches with JKL.

So first side:

BC is congruent  to JK

So second side:

CA is congruent  to KL

So third side:

JL is congruent  to BA

The third side is one of our answer choices.

That answer choice is C.

3 0
2 years ago
10. Which one of the following pairs of numbers contains like fractions?
tangare [24]

Answer:

i think its a 6/7 and 60/70

5 0
2 years ago
1 pt) If a parametric surface given by r1(u,v)=f(u,v)i+g(u,v)j+h(u,v)k and −4≤u≤4,−4≤v≤4, has surface area equal to 1, what is t
natta225 [31]

The area of the surface given by \vec r_1(u,v) is 1. In terms of a surface integral, we have

1=\displaystyle\int_{-4}^4\int_{-4}^4\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv

By multiplying each component in \vec r_1 by 5, we have

\dfrac{\partial\vec r_2(u,v)}{\partial u}=5\dfrac{\partial\vec r_1(u,v)}{\partial u}

and the same goes for the derivative with respect to v. Then the area of the surface given by \vec r_2(u,v) is

\displaystyle\int_{-4}^4\int_{-4}^425\left\|\frac{\partial\vec r_1(u,v)}{\partial u}\times\frac{\partial\vec r_1(u,v)}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\boxed{25}

8 0
3 years ago
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