We know that,
In a right-angled triangle,
Hypotenuse ² = Base ² + Height ²
1 – 10 ² = 6 ² + X ²
Or, X ² = 10 ² – 6 ²
Or, X ² = 100 – 36
Or, X ² = 64
Or, X = √ 64
Or, X = 8 Units
2– X² = 7² + 3²
Or, X² = 49 + 9
Or, X² = 58
Or, X = √58
Or, X = 7.61 Units ( Approx )
3 – 15 ² = EF ² + 9
Or, EF² = 15 ² – 9 ²
Or, EF ² = 225 – 91
Or, EF ² = 134
Or, EF = √ 134
Or, EF = 11.6 Inches ( Approx)
.II} 1 – Here the length of the ladder will be the hypotenuse.
Hence, Hypotenuse = 13 Metre
.Now, The vertical wall will be the height.
Hence, Height = 12 Metre
Distance of the foot of the ladder to the wall will be the base.
Let base be B.
Now, Hypotenuse ² = Base ² + Height ²
Or, 13² = B² + 12²
Or, B² = 13² – 12²
Or, B² = 169 – 144
Or, B² = 25
Or, B = √25
Or, B = 5 Metre
Hence, the distance of the foot of the ladder from the wall is 5 metre apart.
79 is a prime, so we cannot reduce it.
Answer:
2:5
Step-by-step explanation:
7= 16 + 3x
7-16 = 3x
-9 = 3x
x = (-9)/(3)
x = -3
First you have to multiply the 0.6 of the small shakers times two which gives us 1.2 the amount of salt of the large shakers. divide the 18.6 by 1.2 which is 15.5 the amount going into the 8 shakers. Then subtract 15.5 from 18.6 which gives us 3.1. Then you divide that by 0.6 = 5. 5 small shakers can be filled with the remaining salt.
