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3 years ago

How do you write the equation 4x + 2y = 16 in function form? Please answer with an explanation!

1 answer:

kramer3 years ago

3 0

F(x)=-2x+8 This is because f(x) is the same as writing y so therefore you have to change the equation to 4x+2y=16 so you have Y=-2x+8

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Solve by using substitution. Express your answer as an ordered pair.

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(2,3)

Step-by-step explanation:

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2 years ago

Pieces of Mail. The number of pieces of mail

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Answer:

20.8%

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3 years ago

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3 years ago

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3 years ago

Read 2 more answers

URGENT: If θ is a second-quadrant angle and cosθ = -2/3, then tanθ = _____.

dangina [55]

In the second quadrant, both cos and tan are negative while only sin is positive.

To find tan, we will use the following property below:

$\large \boxed{ {tan}^{2} \theta = {sec}^{2} \theta - 1}$

Sec is the reciprocal of cos. If cos is a/b then sec is b/a. Since cos is 2/3 then sec is 3/2

$\large{ {tan}^{2} \theta = {( - \frac{3}{2}) }^{2} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - 1} \\ \large{ {tan}^{2} \theta = \frac{9}{4} - \frac{4}{4} \longrightarrow \frac{5}{4} } \\ \large{tan \theta = \frac{ \sqrt{5} }{ \sqrt{4} } } \\ \large \boxed{tan \theta = \frac{ \sqrt{5} }{2} }$

Since tan is negative in the second quadrant. Hence,

$\large{ \cancel{ tan \theta = \frac{ \sqrt{5} }{2} } \longrightarrow \boxed{tan \theta = - \frac{ \sqrt{5} }{2} }}$

Answer

tan = -√5/2

3 0

3 years ago