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mihalych1998 [28]
3 years ago
9

Adair suggests that they package together the fries and soda in a combo for a $0.75 discount. lf the student council pays $0.85

per trench fry and $1.20 per soda, then how much money will they make if they sell 45 combos? (french fries cost $3.50 and soda costs $2.30 normally)
Please answer I will give you the brainliest!
Mathematics
2 answers:
Zielflug [23.3K]3 years ago
7 0

Answer:

13 :)

Step-by-step explanation:

Ira Lisetskai [31]3 years ago
5 0

Answer:

$58.50

Step-by-step explanation:

It is given that the student council pays

For per french fry = $0.85

For per soda fry = $1.20

Discount on the combo of  fries and soda = $0.75

Total revenue for one combo = $0.85 + $1.20 - $0.75 = $1.30

Since the total revenue for one combo is $1.30, therefore the total revenue for 45 combo is

Total revenue for 45 combo = 45 × $1.30 = $58.50

Therefore, they will make $58.50 if they sell 45 combos.

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Paul picked and bagged a total of 30 pounds of apples on Saturday and Sunday.
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Answer:

he filled 10 bags on sunday

Step-by-step explanation:

if each bag weighs 5 pounds, and he filled 2 on Saturday he used 10 pounds already. that would leave 20 pounds left, 20 ÷ 2 = 10

7 0
2 years ago
Represent the following expression using an exponent
Andrew [12]
12^4 which is equal to 12 times itself 4 times
4 0
2 years ago
What is the difference when the product of 0.3 and 0.4 is subtracted from the sum of 0.3 and 0.4?​
Rudik [331]

Answer:

0.58

Step-by-step explanation:

The first approach to solving the question above is to find the product of 0.3 and 0.4 thus:

0.3 \times 0.4 = 0.12

Next step is to find the sum of 0.3 and 0.4 thus:

0.3 + 0.4 = 0.7

The final step is to find the difference between the two results. Thus:

0.7 - 0.12 = 0.58

Therefore, the product of 0.3 and 0.4 subtracted from the sum of 0.3 and 0.4 is 0.58

7 0
2 years ago
Illustrative Example 1:
dlinn [17]

Given:

The data set is:

87, 84, 85, 85, 86, 90, 79, 82, 78, 76

To find:

The mode of the given data set.

Solution:

We have,

87, 84, 85, 85, 86, 90, 79, 82, 78, 76

Arrange the data values in the ascending order.

76, 78, 79, 82, 84, 85, 85, 86, 87, 90

We know that the mode of date set is the most frequency value of the data set.

From the above data set it is clear that the number 85 has the highest frequency 2.

Therefore, the mode of the data set is 85.

6 0
2 years ago
I need help with #1 of this problem. It has writings on it because I just looked up the answer because I’m confused but I want t
belka [17]

In the figure below

1) Using the theorem of similar triangles (ΔBXY and ΔBAC),

\frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC}

Where

\begin{gathered} BX=4 \\ BA=5 \\ BY=6 \\ BC\text{ = x} \end{gathered}

Thus,

\begin{gathered} \frac{4}{5}=\frac{6}{x} \\ \text{cross}-\text{multiply} \\ 4\times x=6\times5 \\ 4x=30 \\ \text{divide both sides by the coefficient of x, which is 4} \\ \text{thus,} \\ \frac{4x}{4}=\frac{30}{4} \\ x=7.5 \end{gathered}

thus, BC = 7.5

2) BX = 9, BA = 15, BY = 15, YC = y

In the above diagram,

\begin{gathered} BC=BY+YC \\ \Rightarrow BC=15\text{ + y} \end{gathered}

Thus, from the theorem of similar triangles,

\begin{gathered} \frac{BX}{BA}=\frac{BY}{BC}=\frac{XY}{AC} \\ \frac{9}{15}=\frac{15}{15+y} \end{gathered}

solving for y, we have

\begin{gathered} \frac{9}{15}=\frac{15}{15+y} \\ \text{cross}-\text{multiply} \\ 9(15+y)=15(15) \\ \text{open brackets} \\ 135+9y=225 \\ \text{collect like terms} \\ 9y\text{ = 225}-135 \\ 9y=90 \\ \text{divide both sides by the coefficient of y, which is 9} \\ \text{thus,} \\ \frac{9y}{9}=\frac{90}{9} \\ \Rightarrow y=10 \end{gathered}

thus, YC = 10.

4 0
1 year ago
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