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mihalych1998 [28]
3 years ago
9

Adair suggests that they package together the fries and soda in a combo for a $0.75 discount. lf the student council pays $0.85

per trench fry and $1.20 per soda, then how much money will they make if they sell 45 combos? (french fries cost $3.50 and soda costs $2.30 normally)
Please answer I will give you the brainliest!
Mathematics
2 answers:
Zielflug [23.3K]3 years ago
7 0

Answer:

13 :)

Step-by-step explanation:

Ira Lisetskai [31]3 years ago
5 0

Answer:

$58.50

Step-by-step explanation:

It is given that the student council pays

For per french fry = $0.85

For per soda fry = $1.20

Discount on the combo of  fries and soda = $0.75

Total revenue for one combo = $0.85 + $1.20 - $0.75 = $1.30

Since the total revenue for one combo is $1.30, therefore the total revenue for 45 combo is

Total revenue for 45 combo = 45 × $1.30 = $58.50

Therefore, they will make $58.50 if they sell 45 combos.

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What number is 2 tens and 5 ones more than 34
hammer [34]

Answer:

The answer is 59

Step-by-step explanation: so add 2 tens, 5 ones, and 34

2 tens = 20   5 ones = 5    34

20 + 5 + 34 = 59

4 0
3 years ago
A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th
NARA [144]

Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

A = a + (A \cap B)

In which a is the probability that he wins the first race but not the second and A \cap B is the probability that he wins both these races.

By the same logic, we have that:

B = b + (A \cap B)

The probability that he wins both races is 0.5.

This means that A \cap B = 0.5

The probability that he wins the second race is 0.6

This means that B = 0.6

B = b + (A \cap B)

0.6 = b + 0.5

b = 0.1

The probability that he wins the first race is 0.7.

This means that A = 0.6

A = a + (A \cap B)

0.7 = a + 0.5

a = 0.2

A) he wins at least one race.

This is

P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

P = a + b = 0.2 + 0.1 = 0.3

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

6 0
3 years ago
(2.03)
ExtremeBDS [4]
Step 3 is the frist incorrect step it should be: 2x-3=3 or 2x-3=-3
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