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krok68 [10]
3 years ago
13

Simplify 6√125x^3y^9z^6

Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0
<span>6√125x^3y^9z^6 simplifies to 67.082039x^3y^9z^6</span>
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Tina conducted a survey to find the favorite weekend activity of the people in her state. She asked 10 of her neighbors what the
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Answer:

Tina conducted a survey to find the favorite weekend activity of the people in her state. She asked 10 of her neighbors what their favorite weekend activity is. Tina concludes that boating is the favorite weekend activity of the people in her state because 70% of her neighbors like to go boating on weekends.

Use at least two sentences to explain why Tina's sample may not be valid. Make sure to use facts to support your answe

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Solve by graphing. Round each answer to the nearest tenth.<br><br> 6x^2 + 31x = 12
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3 years ago
Scientists estimate that about 14 million species exist, and only about 50% of them have been studied and named. About how many
ra1l [238]

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About 7 million

Step-by-step explanation: because half of 14 is 7 then add the million to it

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Without using a calculator convert the decimal into a fraction<br> 0. 75
mojhsa [17]

Step-by-step explanation:

Decimals can always be put over 1, as they're part of a whole number.

\frac{0.75}{1}

<u>Multiply both numerator and denominator by 100:</u>

<u />\frac{0.75 \times 100}{1\times 100} =\frac{75}{100}

\frac{0.75}{1} \: and \: \frac{75}{100} \: are \: fractions \: of \: 0.75

3 0
3 years ago
The sum of the tens digit and the hundreds digit of a number is three times the units digit. 1/5 of the sum of all three digits
Crazy boy [7]

Answer: The numbers are:

965

875

785

695

Step-by-step explanation:

We have a 3 digit number that can be written as:

a*100 + b*10 + c

Where a, b, and c are single-digit numbers.

a is the hundreds

b is the tens

c is the unit.

We know that:

"The sum of the tens digit and the hundreds digit of a number is three times the units digit."

a + b = 3*c

" 1/5 of the sum of all three digits is 1 less than the units digit."

(a + b + c)/5 = c - 1

Then we have the two conditions:

a + b = 3*c

(a + b + c)/5 = c - 1

From the first one, we can write:

(a + b)/3 = c

Replacing that in the other equation we get:

(a + b + a/3 + b/3)/5 = a/3 + b/3 - 1

(4/3)*(a + b)/5 = (a/3 + b/3) - 1

(4/15)*(a + b) = (a + b)/3 - 1

(4/15)*(a + b) - (a + b)/3 = - 1

-(1/15)*(a + b) = -1

a  = 15 - b

Then we can give different values for b, and find the values of a and c, where a and c must be positive.

b = 9

a = 15 - 9 = 6

Then:

c = (9 + 6)/3 = 5

(notice that a + b = 15, then c will be always equal to 5, reggardless of the values of b and a).

This number will be:

695.

if b = 8, then:

a = 15 - 8 = 7

and c = 5, same as before.

the number is 785.

If b = 7, then:

a = 15 - 7 = 8

The number is 875

if b = 6, then:

a = 15 - 6 = 9

The number is:

965

4 0
3 years ago
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