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krok68 [10]
3 years ago
13

Simplify 6√125x^3y^9z^6

Mathematics
1 answer:
sertanlavr [38]3 years ago
4 0
<span>6√125x^3y^9z^6 simplifies to 67.082039x^3y^9z^6</span>
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PLS HELP Complete the table so that the numbers in each column represent the coordinates of a point on the graph
Natasha2012 [34]

Answer:

1 is 1/2 5 is 2 1/2 and 7 would be 3 1/2

Step-by-step explanation:

4 0
3 years ago
MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

5 0
2 years ago
Micah has two valuable watches.
BlackZzzverrR [31]

Answer:£149

Step-by-step explanation:

8 0
3 years ago
If there are 48 oranges then how many apples are there?
UkoKoshka [18]
If this is a actual question then you are missing parts of it! Please leave a comment with the full question and I would be glad to help you out! If looking at what is given then 0 apples as all that is stated is only 48 oranges and no apples.
5 0
3 years ago
Read 2 more answers
Fine the distance between p(2,8 and q(5,3)
defon
d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}
d = \sqrt{(5 - 2)^{2} + (3 - 8)^{2}}\
d = \sqrt{(3)^{2} + (-5)^{2}}
d = \sqrt{9 + 25}
d = \sqrt{34}
7 0
3 years ago
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