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sashaice [31]
4 years ago
9

What is the solution of this system of linear equations? Y= 2x-3; x= y-3

Mathematics
2 answers:
Vsevolod [243]4 years ago
5 0
We substitute x = y-3 to y = 2x-3

therefore:
y = 2(y-3) - 3
y = 2y - 6 - 3
y-2y = -9
-3y = -9
y = 3

then we find x
x = y-3
= 3-3
x = 0
Ivanshal [37]4 years ago
4 0
X=y-3,yer that’s the answer
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You are basically just adding, so combine like terms.

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The difference of the degrees of the polynomials p(x) = 3x2y2 + 5xy? - x6 and q(x) = 3x5 - 4x3 + 2 is
svet-max [94.6K]

Answer:

The difference of the degrees of the polynomials p (x) and q (x) is 1.

Step-by-step explanation:

A polynomial function is made up of two or more algebraic terms, such as p (x), p (x, y) or p (x, y, z) and so on.

The polynomial’s degree is the highest exponent or power of the variable in the polynomial function.

The polynomials provided are:

p(x) = 3x^{2}y^{2} + 5xy - x^{6}\\\\q(x) = 3x^{5} - 4x^{3} + 2

The degree of polynomial p (x) is:

\text{deg}\ p (x)=6

The degree of polynomial q (x) is:

\text{deg}\ q (x)=5

The difference of the degrees of the polynomials p (x) and q (x) is:

\text{deg}\ p(x)-\text{deg}\ q(x)=6-5=1

Thus, the difference of the degrees of the polynomials p (x) and q (x) is 1.

6 0
4 years ago
The graph of a function f(x) passes through the following points:
Alex

The function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

The graph of a function f(x) passes through the following points: (0,2), (1, 0), (-1,0)

Let

f(x) = ax² + bx + c

Plug x = 0, and y = 2

c = 2 ...(1)

Plug x = 1 and y = 0

a + b + c = 0 ..(2)

Plug x = -1 and y = 0

a - b + c = 0  ...(3)

After solving (1), (2), and (3)

a = -2

b = 0

c = 2

f(x) = -2x² + 2

Thus, the function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

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