Let
x----------> charge per hour to rent a jet sky in dollars
y----------> the total cost to rent a jet sky in dollars
we know that
<u>First Jet Sky Company</u>
---------> equation 
<u>Second Jet Sky Company</u>
---------> equation 
we know that
To find the number of hours for which the costs are the same
equate equation and equation
The intersection both graphs is the solution of the problem
using a graph tool
see the attached figure
the intersection point is 
That means
For 
the cost of the rent is 
in both companies
therefore
<u>the answer is</u>
Answer: 55-1/2w=p
Step-by-step explanation: 55 is the starting weight. Therefore, you need to subtract 55 by 1/2 (the amount of weight he loses each week) times each week. This will determines the weight- (p).
Answer:
It's B
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
Add each sample separately
A.17 B. 47 C. 39 D. 52 E. 45
Then you add them all together which totals 200 sick days
We know that they surveyed 5 schools and 10 students at random from each one. So we want to know the mean of sick days the students took not the schools in all.
So we divide 200/50
And get a mean of 4.
So each student took an average of 4 sick days each in the country.
Answer:
B: 9
Step-by-step explanation:
