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AysviL [449]
3 years ago
11

Which of the following could be the side lengths of a right triangle?

Mathematics
1 answer:
choli [55]3 years ago
8 0
Recall that in a right-triangle, the hypotenuse, or longest side, is √(a²+b²).

\bf \sqrt{4.1^2+6.2^2}\qquad \approx\qquad 7.43303437
\\\\\\
\sqrt{40^2+60^2}\qquad \approx\qquad 72.1110255
\\\\\\
\sqrt{3.2^2+5.4^2}\qquad \approx\qquad 6.27694193
\\\\\\
\sqrt{33^2+56^2}\qquad =\qquad 65

pick your poison.
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What is ​ BC ​ ?<br><br><br> Enter your answer in the box.<br><br> BC=<br> units
kumpel [21]

<u>Answer:</u>

  • The length of BC is 25 units.

<u>Step-by-step explanation:</u>

<u>We know that the triangle is an isosceles triangle. Hence, we know that AB = AC. Let's first solve for x.</u>

  • => 4x + 1 = 2x + 23
  • => 4x - 2x = -1 + 23
  • => 2x = 22
  • => <u>x = 11</u>

<u>Now, let's substitute the value into the expression.</u>

  • => 3x - 8
  • => 3(11) - 8
  • => 33 - 8
  • => <u>25</u>

<u>Hence,</u><u> the length of BC is 25 units.</u>

Hoped this helped.

BrainiacUser1357

5 0
2 years ago
Why is the slope between any two points on a straight line always the same?
mixas84 [53]

Answer:

because it never changes.

7 0
3 years ago
A fisherman can
viva [34]

Answer:

4 [miles].

Step-by-step explanation:

1) the condition 'the entire trip took 5 hours' can be written as (where t_us - time spent upstream, t_ds - time spent downstream)

t_{us}+t_{ds}=5;

2) but the distance [D] upstream is equal the distance downstream, then the condition above can be written:

\frac{D}{V_{us}} +\frac{D}{V_{ds}} =5; \ (V_{us}-rowing \ upstream,V_{ds}-rowing \ downstream);

3) finally,

D=\frac{5V_{us}*V_{ds}}{V_{us}+V_{ds}};

D=5*4/5=4 [miles].

5 0
1 year ago
David had a coupon for the grocery store. He graphed on the x-axis what his total bill would be if he didn’t use the coupon and
vladimir2022 [97]

Answer:

68$ Is your answer

Step-by-step explanation:

Hope this helps

6 0
3 years ago
Read 2 more answers
Please If you can see if you can help on some of my questions!!!!
kvv77 [185]
PQ // BC 

then

Angle P = Angle B, A is common angle the two triangles are similar

AP/AB  = AQ/AC

8/18 = 12/ AC

AC = 12 * 18/8 = 27 (your ans: D)

AQ + QC = AC

QC = AC - AQ = 27 - 12 = 15 (if it was required) 

tan60 = y/8

y = s tan60 = 8sqrt(3)  (B)

Next time, post each question separately. 


6 0
3 years ago
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