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snow_tiger [21]
3 years ago
8

Im lost and I don’t understand what’s going on

Mathematics
2 answers:
andrezito [222]3 years ago
6 0
Same sorry I can’t help
dybincka [34]3 years ago
5 0
After this substitute 4.5 in the equation in your photo then check the answer

You might be interested in
Given a triangle MTN, prove that
cupoosta [38]

Answer:

<em></em>\angle m + \angle t + \angle n = 180<em></em>

<em></em>

Step-by-step explanation:

Required

Show that:

\angle m + \angle t + \angle n = 180^o

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

In the attached triangle, the two angles beside \angle m are alternate to \angle t and \angle n

i.e.

\angle 1 = \angle t

\angle 2 = \angle n

Using angle on a straight line theorem, we have:

\angle 1 + \angle m + \angle 2 = 180

Substitute values for (1) and (2)

\angle t + \angle m + \angle n = 180

Rewrite as:

<em></em>\angle m + \angle t + \angle n = 180<em> -- proved</em>

5 0
3 years ago
What valie of x makes the equation true​
Arada [10]

Answer:

x = 1.25

Step-by-step explanation:

-3x+10 = 5x-8

+3x        +3x

10 = 8x - 8

+8           +8

18 = 8x

x = 18/8

x = 1 1/4 = 1.25  

3 0
3 years ago
Find the value of X. Then find the measure of each labeled angle.
wariber [46]
Both angles WILL have the same measure.

So,

3x-10= x+40 (you have to set the equations equal to one another)


Now, add 10 to both sides.

3x=x+50

Subtract x on both sides.

2x=50

Divide both sides by 2.

x=25

Now, plug in x.

(25 +40)= 65

(3(25)-10)= 65

x equals 25 and both angles are equal to 65. Or "B".

I hope this helps!
~cupcake
5 0
3 years ago
Can anybody answer this for range?
snow_lady [41]

Answer:

The answer is (2, 4)

Step-by-step explanation:

I hope this helps!

8 0
3 years ago
The mean amount of money spent on lunch per week for a sample of 100 students is $21. If the margin of error for the population
Digiron [165]

From the given mean and margin of error, the 99% confidence interval for the mean amount of money spent on lunch per week for all students is:

[$19.5, $22.5].

<h3>How to calculate a confidence interval given the sample mean and the margin of error?</h3>

The confidence interval is given by the sample mean plus/minus the margin of error, hence:

  • The lower bound is the sample mean subtracted by the margin of error.
  • The upper bound is the sample mean added to the margin of error.

For this problem, we have that:

  • The sample mean is of $21.
  • The margin of error is of $1.50.

Hence the bounds are given as follows:

  • Lower bound: 21 - 1.50 = $19.50.
  • Upper bound: 21 + 1.50 = $22.50.

Hence the interval is [$19.50, $22.50].

More can be learned about confidence intervals at brainly.com/question/25890103

#SPJ1

7 0
1 year ago
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