Am I right? I will mark a brainliest! :) there is a picture!

Energy is passed from one organism. To another in a linear sequence we call it a

Mice21 [21]

The linear sequence that passes energy from one organism to another is called the food chain. The energy is transferred starting from the Sun which is necessary for the plant's photosynthesis then move towards animals consuming plants as food. This is usually followed by humans eating animals like pigs and chickens for food.

8 0

4 years ago

Rank these reactions from least to most energetically favorable.

mafiozo [28]

Answer:

From least to most energetically favorable, the reactions are:

Glucose to Glucose-6-P (least) ; Glucose-6-P to Fructose-6-P; ATP to ADP and Pi; PEP to pyruvate (most favorable)

Explanation:

ΔG represents the free energy change that occurs during a chemical reaction. A reaction with negative free energy change is exergonic and spontaneous. Negative free energy change represents the fact that reactants have more free energy than products. The excess of the energy is released during the reaction and makes it a spontaneous process.

q`On the other hand, a reaction with positive free energy change is endothermic and non-spontaneous. These thermodynamically unfavorable reactions are coupled with other exergonic reactions to make them occur.

Among the given example, PEP to pyruvate has the highest negative free energy change (−14.8 kcal/mol) and therefore, is energetically most favorable. On the other hand, "Glucose to Glucose-6-P" has the highest positive free energy charge (+3.3 kcal/mol) making it energetically the most unfavorable reaction.

6 0

3 years ago

The __________ in a bridged network will be the source of the greatest loss in the transmission.

aksik [14]

Answer;

Free Space Path Loss

The Free Space Path Loss in a bridged network will be the source of the greatest loss in the transmission.

Explanation;

-Free-space path loss (FSPL) is the loss in signal strength of an electromagnetic wave that would result from a line-of-sight path through free space (usually air), with no obstacles nearby to cause reflection or diffraction.

-Free-space path loss is proportional to the square of the distance between the transmitter and receiver, and also proportional to the square of the frequency of the radio signal. This value is usually calculated by discounting any obstacles or reflections that might occur in its path.

7 0

3 years ago

What is amylase? A. another name for the large intestine B. an enzyme that breaks down food C. acid in the stomach D. a nutrient

Oksanka [162]

Answer:

B

Explanation:

Amylase is an enzyme that helps digest carbohydrates

7 0

3 years ago

Read 2 more answers

The cross over frequency between linked genes C and D is 40%; between A and D is 35%; between C and A is 5%; between A and E is

nlexa [21]

Answer: The first line shows the Correct order of genes in the chromosome and the second and third lines show the distances between genes.

C ------------ A ---------------------------------- E -------------------- D (Correct order)

/-----5MU--//---------------25 MU-----------//---------10MU-----/ (Distances)

/------------------------------------40 MU ------------------------------/ (Total distance)

Explanation:

We need to know that 1% of recombination frequency = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one results in a recombinant one.

The recombination frequencies between two genes determine their distance in the chromosome, measured in map units. So, if we know the recombination frequencies, we can calculate distances between the four genes in the problem and we can figure the genes order out. This is:

Recombination frequencies:

1% of recombination frequency = 1 map unit (MU)

C-D = 40% = 40 MU

A-D = 35% = 35 MU

C-A = 5% = 5 MU

A-E = 25% = 25 MU

E-D = 10% = 10 MU

Now that we know the distances between pairs of genes, we need to figure out which is the correct order in the chromosome.

C and D are the genes with the biggest distance between them (40MU), which probably means they are in the extremes. The rest of the genes are in the middle.

C ------------------ (40MU) --------------------------------------- D

A is 5 MU apart from C and 35 MU apart from D, which means it is closer to C.

C------ (5MU)----A------------------------------(35 MU)-------D

E is 25 MU apart from A and only 10 MU apart from D, which means it is between A and D, and closer to D

C--------------------A------- (25 MU)---------E----(10MU)-----D

The sum of C-A distance + A-E distance + E-D distance equals the C-D distance. This is:

C-A 5MU + A-E 25MU + E-D 10MU = C-D 40 MU

5 + 25 + 10 = 40

In conclusion, the correct order of the genes in the chromosome is

C ------------ A ---------------------------------- E -------------------- D

/-----5MU--//---------------25 MU-----------//---------10MU-----/

/------------------------------------40 MU ------------------------------/

8 0

3 years ago