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NARA [144]
2 years ago
5

Which equation represents a tangent function with a domain of all Real numbers such that x is not equal to pi over 2 plus pi tim

es n comma where n is an integer?

Mathematics
1 answer:
Rudik [331]2 years ago
7 0

The equation that represents a tangent function with a domain of all real numbers such that x \ne \frac{\pi}2 + n \pi is g(x) = \tan(n \pi - \frac{\pi}2)

<h3>Domain</h3>

The domain of a function is the set of input values the function can take

The domain of the function is given as:

x \ne \frac{\pi}2 + n \pi

<h3>Undefined function</h3>

This means that, we determine the function that would be undefined when the input value equals

x = \frac{\pi}2 + n \pi

From the list of given functions, only function g(x) is undefined at x = \frac{\pi}2 + n \pi

Hence, the tangent function is g(x) = \tan(n \pi - \frac{\pi}2)

Read more about domain at:

brainly.com/question/1770447

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Match the information on the left with the appropriate equation on the right.
kiruha [24]

Answer:

See attachment below

Step-by-step explanation:

For the first option, we are given m = - 2 / 3, b = 3. This is likely in the point - slope form y = mx + b, where m = slope and b = y - intercept. Thus, the equation of the line in point - slope form given this information, should be y = - 2 / 3x + 3. It seems as if none of the following equations match this form, so let us interchange the equation a bit,

y = - 2 / 3x + 3,

y + 2 / 3x = 3,

2x + 3y = 9 - Option C

_______________________________________________________

Next we are given m = - 3 / 2, and that this line passes through the point ( 4, - 1 ). Substitute m as - 3 / 2, x as 4, y as - 1, knowing point ( 4, - 1 ), into the form y = mx + b - solving for b.

- 1 = ( - 3 / 2 )( 4 ) + b,

b = 5,

Thus the equation in point - slope form should be y = - 3 / 2x + 5. None of the choices match this, so let us again alter the equation,

y = - 3 / 2x + 5,

2y = - 3x + 10,

- 2y = 3x - 10 - Option A

_______________________________________________________

( 6, 3 ) and ( 3, 1 ) is given to lie on this line. The slope of the line should be as follows,

Slope = 3 - 1 / 6 - 3 = 2 / 3

Now let us determine the y - intercept ( b ) by substitute one of the points, say ( 6, 3 ). In this case x = 6, and y = 3,

3 = ( 2 / 3 )( 6 ) + b,

b = - 1,

y = 2 / 3x - 1 = Option D

Take a look at the attachment below for further help;

3 0
3 years ago
Alex drew two lines and two transversals. He wants to know the measures of angles 1, 2, and 3. Identify the measure of each angl
emmainna [20.7K]

Answer:

m 1 = 45 degrees because 1 and the angle measuring 135 degrees are supplementary angles.

m 2 = 95 degrees because 2 and the angle measuring 95 degrees are vertical angles.

m 3 = 40 degrees because 1, 2, and 3 form a triangle

Step-by-step explanation:

7 0
2 years ago
A pizza is $6.98. how much is the pizza, with a 50% off discount?
irga5000 [103]
The pizza would cost $3.49 
8 0
4 years ago
40% of 50 is what number
nikitadnepr [17]

20

Step-by-step explanation:

Step 1:

Let the number be 50 and to find 40% of  50 is given interms of expression as follows

To express the percentage the following strategy is used

Eg: 40% = 40/100

∴ To express 40% of 50 is

(40/100)*50

Step 2:

On simplification the above expression we could get

0.4*50

= 20

4 0
3 years ago
Read 2 more answers
If 1200 cm2 of material is available to make a box with a square base and an open top, find the largest possible volume of the b
Colt1911 [192]

Answer:

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

Step-by-step explanation:

Given

Volume of a box = length × breadth × height= l×b×h

In this case the box have a square base. i.e l=b

Volume V = l^2 × h

The surface area of a square box

S = 2(lb+lh+bh)

S = 2(l^2 + lh + lh) since l=b

S = 2(l^2 + 2lh)

Given that the box is open top.

S = l^2 + 4lh

And Surface Area of the box is 1200cm^2

1200 = l^2 + 4lh ....1

Making h the subject of formula

h = (1200 - l^2)/4l .....2

Volume is given as

V = l^2 × h

V = l^2 ×(1200 - l^2)/4l

V = (1200l - l^3)/4

the maximum point is at dV/dl = 0

dV/dl = (1200 - 3l^2)/4

dV/dl = (1200 - 3l^2)/4 = 0

3l^2= 1200

l^2 = 1200/3 = 400

l = √400

I = 20cm

Since,

h = (1200 - l^2)/4l

h = (1200 - 20^2)/4×20

h = (800)/80

h = 10cm

The largest possible volume V is ;

V = l^2 × h

V = 20^2 × 10 = 4000cm^3

4 0
3 years ago
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