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3 years ago

Help please... :) I need help

Mathematics

1 answer:

Reptile [31]3 years ago

7 0

Answer:

arcPR=125

RQ=125

PR=30

AQ=4

im not done yet and im not sure if im right but hope this helps.

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12y+d=−19y+t solve for y?

sergij07 [2.7K]

Without values for the other variables, I assume you're asking for a literal equation.

12y+d=-19y+t
31y+d=t
31y=-d+t
y=(-d+t)/31

8 0

2 years ago

Read 2 more answers

Fabulous fitness charges a one time fee of $90 and an additional $25 per month wonder weights charges a one time fee of only $ 2

Aleksandr-060686 [28]

Answer:

9 months

Step-by-step explanation:

Given

Fabulous fitness charges a one-time fee of $90 and an additional $25 per month

let the number of months be x

and the total charges be y

y= 25x+90---------1

Wonder weights charges a one-time fee of only $ 27 dollars but charge an additional $32 each month

let the number of months be x

and the total charges be y

y= 32x+27------------2

Required

The value of x, that is the number of months

Step two:

Equating both equations we have

25x+90=32x+27

collect like terms

25x-32x=27-90

-7x=-63

7x=63

divide both sides by 7

x= 63/7

x= 9 months

6 0

2 years ago

you are going on vacation and leaving your dog in a kennel. kennel a charges $25 per day which includes a one-time grooming trea

rewona [7]

Answer:

is this a quiz?

Step-by-step explanation:

8 0

2 years ago

Which number has the same value as 20 tens

barxatty [35]

200 has the same value as 20 tens beucase 20*10=200

4 0

3 years ago

A researcher surveyed 150 high school students and found that 68% played a musical insturment. What would be a reasonable range

maria [59]

Answer:

The reasonable range for the population mean is (61%, 75%).

Step-by-step explanation:

The interval estimate of a population parameter is an interval of values that consist of the values within which the true value of the parameter lies with a certain probability.

The mean of the sampling distribution of sample proportion is, $\hat p$ .

One of the best interval estimate of population proportion is the 95% confidence interval for proportion,

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Given:

n = 150

$\hat p$ = 0.68

The critical value of <em>z</em> for 95% confidence level is:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

Compute the 95% confidence interval for proportion as follows:

$CI=\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.68\pm1.96\sqrt{\frac{0.68(1-0.68)}{150}}\\\\=0.68\pm 0.0747\\\\=(0.6053, 0.7547)\\\\\approx (0.61, 0.75)$

Thus, the reasonable range for the population mean is (61%, 75%).

5 0

3 years ago