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kykrilka [37]
3 years ago
14

Identify any zeros of y=x^2+4x+5.

Mathematics
1 answer:
Jet001 [13]3 years ago
3 0

A there are no real zeros

using the discriminant b² - 4ac  to determine the nature of the zeros

for y = x² + 4x + 5 ( with a = 1, b = 4 and c = 5 )

• If b² - 4ac > 0 there are 2 real and distinct zeros

• If b² - 4ac = 0 there is a real and equal zero

• If b² - 4ac < 0 there are no real zeros

b² - 4ac = 16 - 20 = - 4

Since discriminant < 0 there are no real zeros



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Classify each pair of labeled angles of a complementary, supplementary, or neither.
Vsevolod [243]

Answer:

The first one is neither: 90+89=179

The second one could be either supplementary or neither: 63+47=110, but if you add the final angle measure it would be 180

The last one is complementary: 62+29=90

<em>Hope this helps; Please mark Brainliest :)</em>

8 0
3 years ago
The sales of lawn mowers t years after a particular model is introduced is given by the function y = 5500 In(9t+4), where y is t
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20875.2 All you have to do is plug in the numbers to the equation.
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Find the range for the set of data.
Naddika [18.5K]

Answer:

64

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
4) The path of a satellite orbiting the earth causes it to pass directly over two
Naily [24]

Answers:

  • Satellite is approximately <u>2446.43 km</u> from station A.
  • Satellite is approximately <u>2441.61 km</u> above the ground.

=========================================================

Explanation:

I'm assuming tracking stations A and B are at the same elevation and are on flat ground. In reality, this is likely not the case; however, for the sake of simplicity, we'll assume this is the case.

The diagram is shown below. Points A and B describe the two stations, while point C is the satellite's location. Point D is on the ground directly below the satellite. We have these lengths

  • AB = 60 km
  • AD = x
  • CD = h

Focusing on triangle ACD, we can apply the tangent rule to isolate h.

tan(angle) = opposite/adjacent

tan(A) = CD/AD

tan(86.4) = h/x

x*tan(86.4) = h

h = x*tan(86.4)

We'll use this later in the substitution below.

--------------------

Now move onto triangle BCD. For the reference angle B = 85, we can use the tangent rule to say

tan(angle) = opposite/adjacent

tan(B) = CD/DB

tan(B) = CD/(DA+AB)

tan(85) = h/(x+60)

tan(85)*(x+60) = h

tan(85)*(x+60) = x*tan(86.4) .............  apply substitution; isolate x

x*tan(85)+60*tan(85) = x*tan(86.4)

60*tan(85) = x*tan(86.4)-x*tan(85)

60*tan(85) = x*(tan(86.4)-tan(85))

x*(tan(86.4)-tan(85)) = 60*tan(85)

x = 60*tan(85)/(tan(86.4)-tan(85))

x = 153.612786190499

--------------------

We'll use this approximate x value to find h

h = x*tan(86.4)

h = 153.612786190499*tan(86.4)

h = 2441.60531869599

h = 2441.61 km  is how high the satellite is above the ground.

Return to triangle ACD. We'll use the cosine rule to determine the length of the hypotenuse AC

cos(angle) = adjacent/hypotenuse

cos(A) = AD/AC

cos(86.4) = x/AC

cos(86.4) = 153.612786190499/AC

AC*cos(86.4) = 153.612786190499

AC = 153.612786190499/cos(86.4)

AC = 2446.43279498247

AC = 2446.43 km is the distance from the satellite to station A.

6 0
3 years ago
Which graph shows a system of equations with no solutions?
podryga [215]

Graph of Parallel lines shows a system of equations with no solutions

Step-by-step explanation:

Consider a set of equations

7x - 2y = 16\\21x + 6y =24

If we solve this both equations using any one of the solving method, (Substitution method) then we will get

7x-2y=16\\7x=16+2y\\x=\frac{16+2y}{7}

substituting the following x in 2nd equation (21x + 6y = 24) We get

21(\frac{16+2y}{7} )+6y=24\\3(16+2y)+6y=24\\48+6y+6y=24\\12y=24-48\\y=-\frac{24}{12} \\y=-2

Put y= -2 in x equation

x=\frac{16+2(-2)}{7}\\ x=\frac{16-4}{7}\\\x=\frac{12}{7} \\x=1.71

Comparing these (x,y) values we can understand that they never meet at a point

4 0
3 years ago
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