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mixas84 [53]
4 years ago
13

How much water is in the oil at the end of the day

Mathematics
1 answer:
Mademuasel [1]4 years ago
7 0
2 tons of water are in oil by the end of the day


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Arcsin(sin(3pi)) ...?
expeople1 [14]
The solution to the problem is as follows:

arc sin (sin 3pi) = theta 
<span>where theta is the angle ur looking for </span>
<span>so that becomes </span>
<span>sin (theta) = sin 3pi </span>
<span>sin (theta) = 0 </span>
<span>theta = 0, pi
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
6 0
3 years ago
What function to use and how to use it
Lena [83]

That's the wrong right triangle to draw.  Reading the problem carefully we want this one, figure attached.

So we have the usual 30/60/90 triangle but not to scale.  The sides come in ratio 1:√3:2=x:100:hypotenuse.  So

x = 100/√3 ≈ 57.735

We add that to our 133.2 for the total height of the Cyclone, 190.935.

Answer: 190.9

7 0
3 years ago
Anna made 20/28 free throws in basketball this season.To the nearest thousands,what is her free-throw average?
Afina-wow [57]

Answer:

0.714 free throws.

Step-by-step explanation:

Anna made 20 out of 28 free throws.

Free-throw average = \frac{20}{28}  = 0.7142857143 free throws.

This equals 0.714 free throws (answer rounded up to the nearest thousandths)

5 0
4 years ago
Write a fraction less than 1 with a denominator of 6 that is greater than 3/4
serg [7]
The answer you are looking for is 5/6
7 0
4 years ago
Read 2 more answers
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
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