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nataly862011 [7]
3 years ago
14

What is the range in 5.7.12.14.16,16

Mathematics
2 answers:
igor_vitrenko [27]3 years ago
5 0

The range is the highest number minus the lowest number. So in this case it would be:

16 - 5 = 11

Hope this helps! :)

Ber [7]3 years ago
4 0

<u>Answer:</u>

11

<u>Step-by-step explanation:</u>

We are given a data set which includes the following elements:

5, 7, 12, 14, 16, 16

It is a good idea to arrange the data set in an ascending order before working on it but our data set is already arranged in ascending order so we do not need to re-arrange it.

Range is the difference between the highest and the lowest elements of the data set. Here 5 is the lowest number and 16 is the highest.

So range = 16 - 5 = 11


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Answer:

To find part A you need to find common denominator.

1/3 + 3/5=

5/15 + 9/15= 14/15

His mistake for a is that he didn't find the common denominator and that he just added the fraction as it is. So the corrected version would be 14/15.

To find part B you also need to find the least common denominator.

11/12-5/6=

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His mistake was that he didn't find the least common denominator and he subtracted the fraction as it is. The answer corrected would be 1/12.

Step-by-step explanation:

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Answer:

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Vinil7 [7]

Answer:

1.  $33,000

2.  $6077.53

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a)  2.72 seconds

b)  0.96 seconds

4.  189 square meters

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a)  Average Rate of Change = 4 pounds per week, or -4

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Dependent Variable = T

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The value of a tractor V(t) decreases over time, t. Its value is given by:

V(t)=55000-5500t

To find value of tractor after 4 years, we would need to substitute "4" into t and calculate. It is shown below:

V(t)=55000-5500t\\V(4)=55000-5500(4)\\V(4) =33000

The value of the tractor after 4 years is <u>$33,000</u>

<u></u>

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The value of investment that is growing each year, is given by:

f(n)=5000(1.05)^{n}

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1.05 means a 5% growth rate per year

n is the time in years

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The time it takes of pendulum to make one swing is given by the formula:

T(L)=2\pi \sqrt{\frac{L}{32}}

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<u></u>

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y = 2x

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p, A, and H are all independent

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