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Assoli18 [71]
3 years ago
10

Mrs. Raymond gave each of her students 1/12 of a box of crackers. She has 30 students in her class. How many boxes of crackers w

ill she need?
Mathematics
1 answer:
Troyanec [42]3 years ago
5 0
She will need 2 1/2 boxes of crackers.
Work:
1/12 times 30/1 is 30/12 which simplifies to 2 1/2.
I'm not totally sure I'm correct but I hope this helped!
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there are 16 tables in the lunch room.each tables can seat 22 studenrs. how many students can be seated at the at one time
masha68 [24]
16*22=352
352 students
3 0
3 years ago
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Mr. Gurney purchased 3 dozen
DedPeter [7]
If mr Gurney purchased 5 dozen eggs it would be 9.55
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Find the annual rate of interest. Principal = 4600 rupees, Period = 5 years, Total amount = 6440 rupees, Annual rate of interest
Len [333]

The annual rate of interest per year is 8%

<u>Solution:</u>

Given:- Principal (p) = 4600 rupees, Time –Period (t) = 5 years, Total amount(A) = 6440 rupees

First we will calculate the Interest and then using formula of simple interest we will calculate the rate of interest

Interest = Amount – Principal

Interest = 6440  – 4600 = 1840

Now using the formula of simple Interest and on putting values we get,

\text {Simple Interest }=\frac{P \times R \times T}{100}

Where "P" is the principal and "R" is the rate of interest per annum and "T" is the time period

1840=\frac{4600 \times R \times 5}{100}

\begin{aligned} \mathrm{R} &=\frac{1840 \times 100}{4600 \times 5} \\\\ \mathrm{R} &=\frac{1840}{230} \\\\ \mathrm{R} &=8 \% \end{aligned}

Hence, the required rate of interest per year is 8%

6 0
3 years ago
Prove the identity (n-5)^2 - (6n-35)=(n-10)(n-6)
elena-14-01-66 [18.8K]

Answer:

(n-5)^2 - (6n-35)=(n-10)(n-6)

-----------

  • n²-10n+25-6n+35 =
  • n²-16+60 = n²- 10n - 6n + 60 =
  • n(n-10) - 6(n-10) =
  • (n-10)(n-6)
7 0
3 years ago
The function f(x) is graphed on the coordinate plane. What is f(−4) ?
Dmitry_Shevchenko [17]
If you are trying to find the degree of f(-4) the answer is 1.
4 0
3 years ago
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