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Assoli18 [71]
3 years ago
10

Mrs. Raymond gave each of her students 1/12 of a box of crackers. She has 30 students in her class. How many boxes of crackers w

ill she need?
Mathematics
1 answer:
Troyanec [42]3 years ago
5 0
She will need 2 1/2 boxes of crackers.
Work:
1/12 times 30/1 is 30/12 which simplifies to 2 1/2.
I'm not totally sure I'm correct but I hope this helped!
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Translation of a 2D shape..<br> Due in tomorrow, please help! Xx
bazaltina [42]
(5,7) (5,4) (7,4) hope that helps
4 0
3 years ago
If m&lt;7 is 2x + 30 and m&lt;28 is 3x - 10, find the<br> following:
topjm [15]

Answer:

x = 32

m∠7 = 94

m∠8 = 86

m∠3 = 94

Step-by-step explanation:

(2x + 30) + (3x - 10) = 180

5x + 20 = 180

5x = 160

x = 32

m∠7 = 2(32) + 30 = 94

m∠8 = 3(32) - 10 = 86

<u>or</u>

m∠8 = 180 - 94 = 86

<u>m∠3 ≈ m∠7</u> (corresponding angles)

3 0
3 years ago
A profit function is derived from the production cost and revenue function for a given item. The monthly profit function for a c
SpyIntel [72]
Check the picture below.

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5 0
3 years ago
Solve a quadratic equation by factoring j2–30j=0
Lina20 [59]

Answer:

j = 0  or j = 30

Step-by-step explanation:

j² - 30j = 0

Factorise j out of both terms on the left side.

j (j-30) = 0

Apply zero product rule.

j = 0  or j-30 = 0

Find the value of j.

j = 0  or j = 30

4 0
3 years ago
A rectangular parking lot has a perimeter of 820 ft. The area of the parking lot measure SL 42,000 ft
horsena [70]

Answer:

a= 200

b = 210

Step-by-step explanation:

My assumption is, we have to find the length of sides of rectangle

Given

perimeter = 2a + 2b = 820 ft (i) (here a is smaller side and b is larger side)

area = a*b = 42,000 ft^2 (ii)

from eq (1)

2a + 2b = 820

=> 2(a+b) = 820

=> a+b = 820/2

=> a + b = 410

=> a = 410-b   (iii)

putting the value of a in eq(ii), we get

(410-b) *b = 42,000

410b - b^2 = 42,000

0 = b^2 - 410b + 42000

b^2 - 410b + 42000 = 0

b^2- 200b- 210b + 42000 = 0

b(b-200)-210(b-200) = 0

(b-200)(b-210) = 0

or

b= 210 and b = 200

if b is larger side than b =210

By putting value of b in eq(iii),

a = 410 -210 = 200

 

6 0
3 years ago
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