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2 years ago

What is the slope intercept equation of the line below?

Mathematics

1 answer:

antoniya [11.8K]2 years ago

5 0

Answer:

${ \tt{slope, \: m = \frac{1 - ( - 1)}{1 - 0} }} \\m = 2 \\ y - intercept : y = mx + c \\ { \tt{1 = (2 \times 1) + c}} \\ c = - 1 \\ { \boxed{ \bf{y = 2x - 1}}}$

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candace is at a coffee shop and knows she can spend more than $52 before tax she sees this price list in the coffee shop

dimulka [17.4K]

$21+7.50p\leq 52$

<h2>Explanation:</h2>

For inequalities, "a is no more than b" can be written as:

$a\leq b$

Here we know Candace that can spend no more than $52 before tax. She can spend a certain amount of money in both Dark Roast coffee and Morning Blend coffee. So she spends:

2 pounds of Morning Blend coffee.
p pounds of Dark Roast coffee

Therefore:

<u>Amount of money for Morning Blend coffee:</u>

$2\times 10.50=\$21$

<u>Amount of money for Dark Roast coffee:</u>

$p\times 7.50=\$7.50p$

So the total amount of money:

$21+7.50p$

Finally, the inequality becomes:

$21+7.50p\leq 52$

Besides, in order to know how many pounds she can spend let's solve for p:

$7.50p\leq 52-21 \\ \\ 7.50p\leq 31 \\ \\ p\leq 4.13$

So she can spend less that 4.13 pounds.

<h2>Learn more:</h2>

Inequalities: brainly.com/question/12890742

#LearnWithBrainly

7 0

3 years ago

The lengths of brook trout caught in a certain Colorado stream are normally distributed with a mean of 14 inches and a standard

mezya [45]

Answer:

0.6563 or 65.63% of brook trout caught will be between 12 and 18 inches

Step-by-step explanation:

Mean trout length (μ) = 14 inches

Standard deviation (σ) = 3 inches

The z-score for any given trout length 'X' is defined as:

$z=\frac{X-\mu}{\sigma}$ e interval

For a length of X =12 inches:

$z=\frac{12-14}{3}\\z=-0.6667$

According to a z-score table, a score of -0.6667 is equivalent to the 25.25th percentile of the distribution.

For a length of X =18 inches:

$z=\frac{18-14}{3}\\z=1.333$

According to a z-score table, a score of 1.333 is equivalent to the 90.88th percentile of the distribution.

The proportion of trout caught between 12 and 18 inches, assuming a normal distribution, is the interval between the equivalent percentile of each length:

$P(12\leq X\leq 18) = 90.88\% - 25.25\%\\P(12\leq X\leq 18) = 65.63\%$