Answer:
Step-by-step explanation:
1.) y= 1/5x - 2
2.) y = 1x + 2
3.) y = 2x + 4
4.) y = 1x + 4
5.) y = 1/3x - 4
6.) y = 1/2x - 3
Answer:

Step-by-step explanation:
To find the real zeros you must match the function to zero and factor the expression.
We have a polynomial of degree 3.
We try to group the terms to perform the factorization

Now we take (x + 4) as a common factor

If we have an expression of the form
we know that this expression is equivalent to:

In this case

So:

Finally:

The solutions are:

The <em>correct answers</em> are:
C) No: we would need to know if the vertex is a minimum or a maximum; and
C)( 0.25, 5.875).
Explanation:
The domain of any quadratic function is all real numbers.
The range, however, would depend on whether the quadratic was open upward or downward. If the vertex is a maximum, then the quadratic opens down and the range is all values of y less than or equal to the y-coordinate of the vertex.
If the vertex is a minimum, then the quadratic opens up and the range is all values of y greater than or equal to the y-coordinate of the vertex.
There is no way to identify from the coordinates of the vertex whether it is a maximum or a minimum, so we cannot tell what the range is.
The graph of the quadratic function is shown in the attachment. Tracing it, the vertex is at approximately (0.25, 0.5875).
Fill in the given infomation in the appropriate formula.
A = P(1+r)^t
A = $12,000(1.048)^7 ≈ $16,661.35