Answer:
A. Sample Space = S = {(9, 18),(9, 19),(9, 20),(9, 21),(10, 18),(10, 19),(10, 20),(10, 21),(11, 18),(11, 19),(11, 20),(11, 21),(12, 18),(12, 19),(12, 20),(12, 21)}
B. {(9, 18),(10, 18),(11, 18),(12, 18)}
C. {(9, 18),(9, 19),(10, 18)}
D. {(9, 18),(9, 19),(10, 18),(11, 18),(12, 18)}
E. B(complement) ∩C = {(9, 19)}
Step-by-step explanation:
The Sample Space would contain each element of the box A associated with each element of the box B.
A. Sample Space = S = {(9, 18),(9, 19),(9, 20),(9, 21),(10, 18),(10, 19),(10, 20),(10, 21),(11, 18),(11, 19),(11, 20),(11, 21),(12, 18),(12, 19),(12, 20),(12, 21)}
B. Let the Outcomes in the event B, the event that the second resistor has a resistance less than 19 be denoted by J then
J= {(9, 18),(10, 18),(11, 18),(12, 18)}
C. Let the outcomes in the event C, the event that the sum of the resistances is equal to 28 be denoted by L then
L = {(9, 18),(9, 19),(10, 18)}
D. The outcomes in B∪C contains all the elements of B and C
B∪C=J∪L= {(9, 18),(9, 19),(10, 18),(11, 18),(12, 18)}
E. B complement contains those elements of the Sample Space which are not the elements of Set B.
B complement= S-B= {(9, 19),(9, 20),(9, 21),(10, 19),(10, 20),(10, 21),(11, 19),(11, 20),(11, 21),(12, 19),(12, 20),(12, 21)}
B(complement) ∩C contains those elements of B and C which are common to both B complement and C.
B(complement) ∩C = {(9, 19)}
