Suppose that the pedigree shown in the transparency is for a trait caused by recessive allele.is it possible to infer from the p
edigree whether or not I-1 and I-2 are carriers of the allele
1 answer:
As we can see in the pedigree, both of the parents do not possess the trait, but one of the four offspring (marked with red) is expressing the trait.
Since the trait is recessive, the only way that is possible that the parents who do not possess the trait to have the offspring with the trait is that the parents are heterozygous for the trait. Meaning that both of the parents have one dominant allele and one recessive allele.
Since the trait is recessive, the only way that is possible that the parents who do not possess the trait to have the offspring with the trait is that the parents are heterozygous for the trait. Meaning that both of the parents have one dominant allele and one recessive allele.
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Answer:
Frequency of p
Frequency of p
Number of individuals with homozygous dominant (AA)
Number of individuals with heterozygous (Aa)
Number of individuals with homozygous recessive (aa)
Explanation:
Out of 100 people, 10 have albino skin (aa)
So, the frequency of homozygous recessive individuals is
Now, q will be
As per Hardy Weinberg's equation -
Substituting the value of q in above equation, we get -
Now the frequency of homozygous dominant (AA) will be
Hence, out of 100 people people are homozygous dominant (AA)
Like wise out of 100 people people are homozygous recessive (aa)
As per As per Hardy Weinberg's equation-
Substituting the values in above equation, we get -
So, out of 100 people people are heterozygous (Aa)