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ch4aika [34]
3 years ago
13

Ann​'s car can go 312 miles on 8 gallons of gas. During a drive last​ weekend, Ann used 3 gallons of gas. How far did she ​drive

? Explain how the problem changes if you were given the distance Ann drove last weekend instead of how much gas she used.
sorry if theres typos
Mathematics
1 answer:
larisa [96]3 years ago
7 0
The answer is 117 miles and if you were given the miles intead multiply 117 (or whatever the number would havw been) by 8 then divid th product by 312 to get the amount of gas used
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I need help on this one aswell if anyone wants to help me.
Lelechka [254]

Answer:

y=63

Step-by-step explanation:

7 0
2 years ago
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Ethan Planted a tree that was 1.85 meters tall. Several years later, the tree is 5.30 meters tall. Which equation can be used to
Sergeu [11.5K]
Answer: B. 1.85 + x = 5.30

Explanation:

The starting height of the tree was 1.85 meters. To find the number of meters the tree grew, you would subtract the current height from the previous height.
5.30-1.85=x. This equation is the same as 1.85 + x = 5.30 if you switch the 5.30 and x.
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3 years ago
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Find the area of the parallelogram with a base of 12 units and height of 8 units. Use your rectangle from the previous question
Troyanec [42]

Answer:

96 units^2

Step-by-step explanation:

A of parallelogram =base×height

12×8= 96 units^2

8 0
2 years ago
An object is launched from a launching pad 144 ft. above the ground at a velocity of 128ft/sec. what is the maximum height reach
ollegr [7]

Answer:

18) a. h(x) = -16x² + vx + h(0) ⇒ h(x) = -16x² + 128x + 144

b. The maximum height = 400 feet

c. Attached graph

19) The rocket will reach the maximum height after 4 seconds

20) The rocket hits the ground after 9 seconds

Step-by-step explanation:

* Lets study the rule of motion for an object with constant acceleration

# The distance S = ut ± 1/2 at², where u is the initial velocity, t is the time

  and a is the acceleration of gravity

# The vertical distances h in x second is h(x) - h(0), where h(0)

   is the initial height of the object above the ground

∵ h(x) = vx + 1/2 ax², where h is the vrtical distance, v is the initial

  velocity, a is the acceleration of gravity (32 feet/second²) and x

  is the time

18)a.

∵ The value of a = -32 ft/sec² ⇒ negative because the direction

   of the motion

  is upward

∴ h(x) - h(0) = vx - (1/2)(32)(x²) ⇒ (1/2)(32) = 16

∴ h(x) = vx - 16x² + h(0)

∴ h(x) = -16x² + vx + h(0) ⇒ proved

* Find the height of the object after x seconds from the ground

∵ h(0) = 144 and v = 128 ft/sec

∴ h(x) = -16x² + 128x + 144

b.

* At the maximum height h'(x) = 0

∵ h'(x) = -32x + 128

∴ -32x + 128 = 0 ⇒ subtract 128 from both sides

∴ -32x = -128 ⇒ ÷ -32

∴ x = 4 seconds

- The time for the maximum height = 4 seconds

- Substitute this value of x in the equation of h(x)

∴ The maximum height = -16(4)² + 128(4) + 144 = 400 feet

c. Attached graph

19)

- The object will reach the maximum height after 4 seconds

20)

- When the rocket hits the ground h(x) = 0

∵ h(x) = -16x² + 128x + 144

∴ 0 = -16x² + 128x + 144 ⇒ divide the two sides by -16

∴ x² - 8x - 9 = 0 ⇒ use the factorization to find the value of x

∵ x² - 8x - 9 = 0

∴ (x - 9)( x + 1) = 0

∴ x - 9 = 0 OR x + 1 = 0

∴ x = 9 OR x = -1

- We will rejected -1 because there is no -ve value for the time

* The time for the object to hit the ground is 9 seconds

8 0
3 years ago
21 is 20% of what number
Ksenya-84 [330]

Answer:

21 is 20% of 105

Step-by-step explanation:

20% * x = 21

20/100 * x = 21

x = 21 * 100/20

x = 105

If you are using a calculator, simply enter 21×100÷20, which will give you the answer.

6 0
3 years ago
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