Answer:
4th term = 29
to generate the terms, substitute n = 2, 3, 4 into the rule
noting that b(1) = - 7
b(2) = b(2 - 1) + 12 = b(1) + 12 = -7 + 12 = 5
b(3) = b(3 - 1) + 12 = b(2) + 12 = 5 + 12 = 17
b(4) = b(4 - 1) + 12 = b(3) + 12 = 17 + 12 = 29
<em>Answer:
</em>
<em>Elena's running speed is 5 miles/hour
</em>
<em>Explanation:
</em>
<em>The speed is defined as the covered distance per unit time
</em>
<em>In the problem, we have:
</em>
<em>The distance covered is the length (circumference) of the circular track which is given as of a mile.
</em>
<em>We are also given that she completes each lap (she completes of a mile) in of an hour
</em>
<em>
</em>
<em>To get her speed, we will divide the distance covered by the time taken to cover this distance
</em>
<em>This is done as follows:
</em>
<em>speed = miles/hour
</em>
<em>This means that:
</em>
<em>Elena can run 5 miles each hour</em>
By shesney <3
Answer:
77 hours
Step-by-step explanation:
5x7= 35
3x7=21
1x7=7
1x7=7
1x7=7
35+21+7+7+7=77
Answer:
D
Step-by-step explanation:
yes it is.
start by multiply by 4 to get rid of the fraction on x
4 () = 4(4) + 4()
x = 16 + 8y/3
Then by 3 to get rid of that one
3(x) = 3(16) + 3()
3x = 48 + 8y
Then subtract 8y from both sides to get
3x - 8y = 48
The child crawled 18 meters in 823 seconds.
Given:
A child is crawling at a pace of 176 inches every 3.37 minutes.
To find:
The distance covered (in meters) by a child in 823 seconds.
Solution:
Distance covered by a child in 3.37 minutes = 176 inches
Distance covered by a child in a 1 minute =
1 minute = 60 seconds
Distance covered by a child in 60 seconds =
Distance covered by a child in a 1 second:
Distance covered by a child in 823 seconds:
In 1 meter there are 39.37 inches.
The child crawled 18 meters in 823 seconds.
Learn more about the unitary method here:
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