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2 years ago

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Mathematics

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dsp732 years ago

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Refer to the attachment for answer

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Write the equation of the line in point-slope form of the given point and slope. This is an essay style question. If you hit the

svp [43]

Answer:

Step-by-step explanation:

The point-slope form of the equation will be expressed as;

y - y0 = m(x-x0) where;

m is the slope

(x0, y0) is the point on the line

Given

Slope m = 3/7

Point (x0, y0) = (7, -2)

Substitute into the equation;

y - y0 = m(x-x0)

y - (-2) = 3/7 (x - 7)

<em>Hence the equation in point-slope form is y + 2 = 3/7(x-7)</em>

3 0

2 years ago

Help me with this please!!!!

sveticcg [70]

Answer:

option c is the correct answer

6 0

3 years ago

Read 2 more answers

M is directionly proptional to r squared

sergejj [24]

9514 1404 393

Answer:

A) 504

B) 8

Step-by-step explanation:

The statement of proportionality can be written as the equation ...

m = kr²

Then we can find k from ...

k = m/r² = 14/2² = 7/2

That is, ...

m = (7/2)r²

Using this relation, we can find m for r=12:

m = (7/2)·12² = 7·72

m = 504 . . . for r = 12

And, we can use the same equation to solve for r when m=224.

224 = 7/2·r²

r² = 64

r = √64

r = 8 . . . for m = 224

4 0

2 years ago

20 POINTS!!!! PLEASE ANSWER ALL OF THEM CORRECTLY AND EXPLAIN WHY ITS THE ANSWER!

slavikrds [6]

Answer:

Step-by-step explanation: 4 ratio is bigger than 3

5 0

2 years ago

Help with Algebra 2: 1. <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%

Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

1. Given the expression

$\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }$

Note that

$\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}$

When dividing $\sqrt[7]{x^5}$ by $\sqrt[4]{x^2},$ we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

$\dfrac{5}{7}-\dfrac{2}{4}=\dfrac{5}{7}-\dfrac{1}{2}=\dfrac{5\cdot 2-1\cdot 7}{14}=\dfrac{3}{14}$

and the result is $x^{\frac{3}{14}}=\sqrt[14]{x^3}$

2. Given equation $3\sqrt[4]{(x-2)^3} -4=20$

Add 4:

$3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24$

Divide by 3:

$\sqrt[4]{(x-2)^3} =8$

Rewrite the equation as:

$(x-2)^{\frac{3}{4}}=8\\ \\(x-2)^{\frac{3}{4}}=2^3$

Hence,

$\left((x-2)^{\frac{3}{4}}\right)^{\frac{4}{3}}=(2^3)^{\frac{4}{3}}\\ \\x-2=2^{3\cdot \frac{4}{3}}\\ \\x-2=2^4\\ \\x-2=16\\ \\x-2+2=16+2\\ \\x=18$

3 0

2 years ago

I have ten minutes to send it in.​

I have ten minutes to send it in.