Step-by-step explanation:
(i). a+(b+c) = (a+b)+c
-35+(10-5) = (-35+10)+(-5)
-35+5 = -25-5
-30 = -30
(ii). a×(b+c) = a×b + a×c
-35 × [10+(-5)] = -35×10 + -35×-5
-35 × (10-5) = -350 + 175
-35 × 5 = -350 + 175
-175 = -175
I believe the correct answer is a hope this helps
So r+c=42
c=4+r
subsitute c=4+r for r in r+c=42
r+4+r=42
add like terms
2r+4=42
subtract 4 from both sides
2r=38
divide both sides by 2
r=19
rob=19
subsitute r=19 for r in c=4+r
c=19+4
carly=23
The point of intersection of the two lines is at (1,-1)
<h3>System of equation</h3>
The given system of expression is shown below
x - 2y = 3
5x + 3y = 2
The solution to the system of equation is the point of intersection
From equation 1
x = 3 + 2y
Substitute into 2
5(3+2y) + 3y = 2
15 +10y + 3y = 2
13y = -13
y = -1
Substitute y = -1 into 3
x = 3 + 2y
x = 3+(-2)
x = 1
Hence the point of intersection of the two lines is at (1,-1)
Learn more on system of equation here: brainly.com/question/25976025
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Answer:
5
Step-by-step explanation:
2+4+6+8 = 20
20 / 4 = 5
