All categories

3 years ago

Which equation, in point-slope form, passes through (-2, 4) and has a slope of 3?

Mathematics

1 answer:

igor_vitrenko [27]3 years ago

7 0

Answer:

Step-by-step explanation:

The formula is Y-Y1= M(X-X1)

So y-4=3(x+2)

You might be interested in

How to use Pythagorean theorem to find the right triangle side length

MrRissso [65]

Answer:

You would use a^2 + b^2 = c^2

Step-by-step explanation:

a and b are the shorter side of the triangle whereas c is the hypotenuse or longest side of the triangle

5 0

3 years ago

pychu [463]

Answer:

B 8.56

this is the answer because you simply add what he bought so 1.13+1.13+1.76 which is 4.02 then subtract what he started with which was 12.58 so 12.58-4.02 is 8.56 so that's your answer

8 0

2 years ago

Read 2 more answers

(x-2)e2/3=49 <img src="https://tex.z-dn.net/?f=%28x%20-%202%29%20%5E%7B2%20%5Cdiv%203%7D%20%20%3D%2049%20" id="TexFormula1" t

fredd [130]

$\bf (x-2)^{2\div 3}=49\implies (x-2)^{\frac{2}{3}}=7^2\implies \stackrel{\textit{raising both sides by }\frac{3}{2}}{\left( (x-2)^{\frac{2}{3}} \right)^{\frac{3}{2}}=(7^2)^{\frac{3}{2}}} \\\\\\ (x-2)^{\frac{2}{3}\cdot \frac{3}{2}}=7^3\implies (x-2)^1=7^3\implies x=7^3+2\implies x=345$

4 0

3 years ago

−8x+4y=24 −7x+7y=28 What is the solution?

SVETLANKA909090 [29]

−8x + 4y = 24 -- (1)
−7x + 7y = 28 -- (2)

Eqn (1) & (2) are simplified as

y - 2x = 6 -- (3)
y - x = 4 -- (4)

By making y the subject of formula in (4), we have

y = x + 4 -- (5)

Substitute x + 4 for y in (3), then

x + 4 - 2x = 6
x - 2x = 6 - 4
- x = 2
x = - 2.

Substitute - 2 for x in (5), then

y = - 2 + 4
y = 2.

Therefore, (x, y) = (- 2, 2) ...Ans.

5 0

3 years ago

Please help me find the total area of the composite figure below (geometry)

Akimi4 [234]

Answer:

lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$ ⇒ Answer D is correct

Step-by-step explanation:

First, let us find the area of the semi-circle.

Area = $\frac{1}{2}$ × π × r²

Given that,

diameter of the semi-circle is ⇒ l

∴ radius ⇒ l / 2

Let us find it now.

Area = $\frac{1}{2}$ × π × r²

Area = $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

Secondly, let us find the area of the rectangle.

Area = length × width

Given that,

length ⇒ l

width ⇒ w

Let us find it now.

Area = length × width

Area = l ×w

Area = lw

And now let us find the total area.

Total area = Area of the rectangle + Area of the semi - circle

Tota area = lw + $\frac{1}{2}$ × π × $(\frac{l}{2} )^{2}$

8 0

2 years ago