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max2010maxim [7]
3 years ago
8

The point-slope form of the equation of a line that passes through points (8, 4) and (0, 2) is y – 4 =1/4 (x – 8). what is the s

lope-intercept form of the equation for this line? y =1/4 x – 12 y =1/4 x – 4 y =1/4 x 2 y =1/4 x 6
Mathematics
1 answer:
aniked [119]3 years ago
5 0
I think the answer is y=1/4x+2.

Hope that helps!!!
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A pair of headphones is on sale for 15% off. What percent of the regular price is the sale price? Explain your thinking.
Elina [12.6K]

Answer:

85%

Step-by-step explanation:

Generally, you pay 100% of the total cost. However, you get 15% off. This means that all you have to do is 100-15 to get 85.

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What is theory of demand?<br>​
Yuri [45]

Answer:

Demand theory is an economic principle relating to the relationship between consumer demand for goods and services and their prices in the market. ... As more of a good or service is available, demand drops and so does the equilibrium price.

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Use a number line to explain why --15 ÷ 3 =-15
Diano4ka-milaya [45]
It's equal to -15 because you are dividing by an negative and if it's only 1 negative number in your equation then your answer will be a negative and if it's 2 negatives then it would be a positive answer
7 0
3 years ago
NEED HELP! ASAP PLEASE!
Doss [256]

Answer:

(0,-41)

Step-by-step explanation:

You can see that for each 9 units that x goes up, y goes up by 19. If we continue this pattern, it will take 2 more jumps of 9 units for the x value to be 0 or to reach the y intercept. Adding 19 twice to -79 gives -41. Hope this helps!

7 0
3 years ago
Given f(x)=-1/7√16-x^2 find f^-1(x)
Vera_Pavlovna [14]

Answer:

f^{-1}(x)=\pm \sqrt{49x^2-16}

Not a function.

Step-by-step explanation:

The given function is;

f(x)=-\frac{1}{7}\sqrt{16-x^2}

Let y=-\frac{1}{7}\sqrt{16-x^2}

Interchange x and y;

x=-\frac{1}{7}\sqrt{16-y^2}

Solve for y;

-7x=\sqrt{16-y^2}

Square both sides

(-7x)^2=(\sqrt{16-y^2})^2

49x^2^2=16-y^2

49x^2^2-16=y^2

y=\pm \sqrt{49x^2-16}

The inverse is

f^{-1}(x)=\pm \sqrt{49x^2-16}

f^{-1}(x)=\pm \sqrt{49x^2-16} is not a function because one x-value maps onto to different y-values.

6 0
3 years ago
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