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Simora [160]
3 years ago
15

Using significant digits, determine the product of 3.865 and 2.4.

Mathematics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

3.865 - has 4 significant digits.

2.4 -  has 2 significant digits.

Product = 3.865 × 2.4 = 9.276

So,

9.276 has 4 significant digits.

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The expression below represents the number of boxes of cookies sold by a girl scouts troop with 14 members at the school fair, w
Zinaida [17]
I think it would be The first term indicates that the 14 girl scouts each sold 22 boxes of cookies per additional day of the fair. The second term indicates that the 14 girl scouts each sold 25 boxes of cookies on the first day of the fair.
4 0
3 years ago
Penny's function has an output that is four more than three times the input. Johns function expressed in slope-intercept form is
jonny [76]
John's function : y = 3.5x - 4
Penny's function : y = 3x + 4

C. John's function has a greater rate of change, because 3.5 > 3
5 0
3 years ago
Find the missing factor BBB that makes the equality true. -35x^6=(-5x^2)(B)−35x 6 =(−5x 2 )(B)minus, 35, x, start superscript, 6
Sveta_85 [38]

Answer:

B=7x^4

Step-by-step explanation:

The given equality is

-35x^6=(-5x^2)B

Take the term (-5x^2) to the left hand side. This means the term -35x^6 will be divided by (-5x^2)

\dfrac{-35x^6}{(-5x^2)}=B

Now since both the numerator and denominator have negative sign the value of fraction will be positive.

\dfrac{35x^6}{(5x^2)}=B

Now 5\times 7=35 and x^{6-2}=x^4

7x^4=B

So, the missing factor B=7x^4

4 0
2 years ago
A real estate developer is considering investing in a shopping mall on the outskirts of Atlanta, Georgia. Three parcels of land
Arada [10]

Answer:

Step 1: The null and alternative hypothesis for the one way analysis of variance is,

H₀ : There is no difference in the means of each area.

H₁ : At least one mean is different.

The objective of this question is to test whether the income of the three areas are significantly different.

Step 2: The problem states to use 0.05 significance level.

Step 3: The test statistic follows the F-distribution.

Step 4: Decision rule is based on the critical value.

Numerator degrees of freedom is,

K - 1 = 3 - 1

= 2

Denominator degrees of freedom is 2.

n - k = 12 - 3

= 9

Using the F-distribution table for ∝=0.05 with numerator and denominator degrees freedom, the critical value is 4.26. The decision rule is to reject H₀ if the computed value of F exceeds 4.26.

Step 5: Calculations.

Using Excel follow the steps mentioned below.

1. Import or type the data into spreadsheet.

2. Data--------> Data Analysis----------> Anova: Single Factor, click OK.

3. Select Input Range, make a tick mark on Labels in the first row, enter 0.05 for alfa.

4. Click OK.

The obtained output for the one-way ANOVA is,

[ find the figure in attachment]

From the obtained output, the computed test statistic value, F = 14.18 , which is greater than the critical value of 4.26. So, reject H₀

Step 6: Interpretation. The average income of each area is different. It can be concluded that the average income is significantly different .

4 0
3 years ago
use < or > to compare 13 ×(54 +28) and 13 × 54 + 28 without calculating. Explain your reasoning
Firdavs [7]
What do you mean by without calculating?

6 0
2 years ago
Read 2 more answers
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