Answer:
a) 6076 m
b) 43.33 m/s
c) 68 m/s
Explanation:
(a) If the airplane rounds half the circle in 156s, its displacement is the circle diameter in 156s, or twice the circle's radius
s = 2r = 2* 3.38km = 6.76 km or 6760 m
(b) The average velocity would be displacement over unit of time
v = s/t = 6760 / 156 = 43.33 m/s
(c) The length of the chord it's swept in 156s is half of the circle perimeter
c = πr = π3.38 = 10.62 km or 10620 m
The airplane average speed is its chord length over a unit of time
c / t = c / 156 = 68 m/s
Answer:
The amplitude, in meters, of the resulting simple harmonic motion of the block 1/40 m
Explanation:
given information:
the block mass, m = 0.1 kg
spring of force constant, k = 40 N/m
release at t = 0
the formula for simple harmonic motion is
F = kx
where
F = force (N)
k = spring of force constant (N/m)
x = amplitude (m)
thus,
F = kx
x = F/k
= m g/k
= 0.1 x 10/40
= 1/40 m
J.J. Thomson's experiments provided evidence that an atom B.contains negatively charged particles.
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Answer:
9.0 units
Explanation:
The magnitude of the electrostatic force between two charged objects is given by Coulomb's law:
where:
is the Coulomb's constant
are the two charges of the two objects
r is the separation between the two charges
The force is:
- Attractive if the charges have opposite signs
- Repulsive if the charges have same sign
In this probleem, the initial force between the two objects is
F = 18.0 units
Then, the charge of object 1 is halved, so the new charge is
Therefore the new force is
So, the force will also halve: therefore, the new force will be 9.0 units.