1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
riadik2000 [5.3K]
3 years ago
12

When rutherford bombarded thin gold foil with a-particles,he found that some a-particles were deflected through large angles. Wh

ich statement explains this deflection?
Physics
1 answer:
lord [1]3 years ago
3 0

Answer:

the nucleus of the atom you have conserved almost all its mass in a very small volume

Explanation:

In Rutherforf's experiment, most alpha particles had few deflections, eg a few of them were deflected at small angles, a much smaller number deflected at large angles, and very few were deflected.

The explanation that I found for this is that if all the mass and the positive charge of the atom is in a small volume, they could specifically calculate this the relationship of the volumes,

          V_atom / V_nucleo = 10⁴

Therefore, the phrase that explains the observing phenomenon is that the nucleus of the atom has concentrated almost all its mass, very small emolument and in that same volume is all the positive charge of the atoms.

In summary, the phrase that describes the process is:

  the nucleus of the atom you have conserved almost all its mass in a very small volume

You might be interested in
How do gases respond to changes in pressure and temperature?
kakasveta [241]
They compress or expand depending on amount of pressure or depending on the temperature
6 0
3 years ago
Read 2 more answers
An 8 kg mass moving at 8 m/s collides with a 6 kg mass
steposvetlana [31]

Answer:

10 m/s

Explanation:

Momentum before collision = momentum after collision

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

(8 kg)(8 m/s) + (6 kg)(6 m/s) = (8 kg)(5 m/s) + (6 kg) v

64 kg m/s + 36 kg m/s = 40 kg m/s + (6 kg) v

60 kg m/s = (6 kg) v

v = 10 m/s

3 0
4 years ago
When is the magnitude of the acceleration of a mass on a spring at its maximum value?
DiKsa [7]

Answer:

D

Explanation:

Now we know that Force is the rate of change of momentum meaning

F= mv/t

But

mv/t = Ke

v/t = ke/m

a= ke/m

Where a is acceleration

K is constant of proportionality of tension on a spring

e is the extension substended by a string.

From the formula of acceleration we can see that as mass decreases acceleration increases so we can see that m = 1

We would have a maximum value of acceleration.

6 0
4 years ago
Determine the momentum of a 15,000 kg truck traveling at 15 m/s
S_A_V [24]

Answer:

mass*velocity=1.5*10^4 * 15

= 22.5*10^4

6 0
3 years ago
A stone of mass m is thrown upwards at an angle φ. The moment the stone leaves your hand it has an acceleration (friction is neg
Lelechka [254]
The correct answer is:

= g

Explanation:

When the object leaves the hand it has a force acted on it mainly it’s weight.
5 0
3 years ago
Other questions:
  • Which explanation most accurately describes convection within the ocean
    12·1 answer
  • What does the statement what does the statement 10 m/s to the north describe
    10·2 answers
  • the rover uses 4GHz frequency to transmit the picture. The rover’s transmission power is 200W. The transmission antenna gain is
    7·1 answer
  • PLEASE HELP! What type of ions are electrons colliding with to cause resistance in a circuit?
    10·1 answer
  • An enconomy car has a mass of 800 kg. What is the weight of the car?
    11·2 answers
  • Any two instruments based on Pascal's law​
    8·1 answer
  • Cuando habla una persona, ¿por qué identificas que se trata de un hombre,una mujer o un niño​
    13·1 answer
  • Which of the following is characteristic of the elements in a pattern?
    10·1 answer
  • What is the net force if you pull a cart to the right with 5N of
    5·1 answer
  • What is the primary function of the lower
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!