Let i = sqrt(-1) which is the conventional notation to set up an imaginary number
The idea is to break up the radicand, aka stuff under the square root, to simplify
sqrt(-8) = sqrt(-1*4*2)
sqrt(-8) = sqrt(-1)*sqrt(4)*sqrt(2)
sqrt(-8) = i*2*sqrt(2)
sqrt(-8) = 2i*sqrt(2)
<h3>Answer is choice A</h3>
Basic method is Synthetic Division and Factor Theorem
Step-by-step explanation:
For higher-degree equations, the question becomes more complicated than others: cubic and quadratic equations can be solved by similar formulas.
Hence, to avoid those circumstances we can use Synthetic Division and Factor theorem to determine the squares of the given polynomial those who have order higher than 2.
A squared +b squared= c squared
a squared+7 squared =10 squared
a squared + 49= 100
Then subtract 49 from 100 which is 51. Then your square root that number which is 7.14143
