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drek231 [11]
4 years ago
7

PLEASE HELP!!

Mathematics
1 answer:
Nookie1986 [14]4 years ago
6 0
B is the answer to this question
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A number divided by 43 has a quotient of 3 and a remainder of 28. Find the number
svp [43]
You are given the unknown number which has a quotient of 3 and a remainder of 28. This means that 3 is the whole number from the division of the unknown number and 43 and 28 is the decimal, 3.28. Also, the number is divided by 43 too. Let us denote n as the number so we have n/43. Then equate the n/43 to 3.28.  

n/43 = 3.28
n = 43 (3.28)
n = 141.04  
<span>The number is 141. 04</span>
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3 years ago
Real Numbers:Question 6
inessss [21]

Answer:

o45

Step-by-step explanation:

Because 45 is the largest number.

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3 years ago
If a triangle had a height of 14 inches and a base of 9 inches what’s it area
OverLord2011 [107]
Use 1/2 bh as the formula
6 0
3 years ago
Read 2 more answers
Liz and Rick are squeezing lemons for a lemonade stand. Liz squeezed 18 lemons in 6 minutes. Rick squeezed 24 lemons in 12 minut
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Answer:

Liz

Liz because when having the same common denominator,

Liz=2/6    and Rick=3/6

So, I would go with Liz.

6 0
3 years ago
Determine the equation of the line that passes through the given points. (If you have a graphing calculator, you can use the tab
Jlenok [28]

Answer:

c). y = 2

Step-by-step explanation:

We can check a line by inputting the x and y from (x, y) into the equation.

For a. y = 2x we get

2 = 2*10 and 2 = 2*(-3), both of those are false

For b. y = 2x - 3 we get

2 = 2*10 - 3 and 2 = 2*(-3) + 10, both of those are false again

For c. y = 2 we get

2 = 2 and 2 = 2, both of those are true, so this is the right answer.

For d. y = 2x + 10 we get

2 = 2*10 + 10 and 2 = 2*(-3) + 10, both of those are false

Alternatively, we can solve the equation y = ax + b (this gives a single answer for any two points with different x's).

y = ax + b

We input (x, y) as (10, 2) and (-3, 2)

2 = a*10 + b = 10a + b

2 = a*(-3) + b = b - 3a

so we have

10a + b = b - 3a

13a = b - b

13a = 0

a = 0

Now we ca use a = 0 to solve either of the equations above:

2 = 10a + b

2 = 10*0 + b

2 = b

so with a=0 and b=2 we get the answer

y = 0*x + 2

y = 2

Which brings us to answer c. again.

6 0
3 years ago
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