the gas left in an used aerosol can is at a pressure of 103 kPa at 25 degrees celsius if this can be thrown into fire what is th
2 answers:
Answer:
415.11 kPa
Explanation:
The gas law to be applied here is Gay-Lussac's law. Gay-Lussac's law states that the pressure of a given mass of gas is directly proportional to it's temperature (in kelvin) provided volume remains constant.
The formula for the law is
P₁/T₁ = P₂/T₂
where P₁ is initial pressure (103 kPa)
P₂ is final pressure (<u>unknown</u>)
T₁ is initial temperature (25°C + 273 = 298K)
T₂ is final temperature (928°C + 273 = 1201K)
From the formula,
103/298 = P₂/1201
P₂ =
P₂ = 415.11 kPa
415.11 kPa is the pressure of the gas when it temperature reaches 928°C.
Hello!
The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa
To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:
Have a nice day!
The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa
To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:
Have a nice day!
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