Question

the gas left in an used aerosol can is at a pressure of 103 kPa at 25 degrees celsius if this can be thrown into fire what is the pressure of gas when it's temperature reaches 928 degrees Celsius

Answer 1

Answer:

415.11 kPa

Explanation:

The gas law to be applied here is Gay-Lussac's law. Gay-Lussac's law states that the pressure of a given mass of gas is directly proportional to it's temperature (in kelvin) provided volume remains constant.

The formula for the law is

P₁/T₁ = P₂/T₂

where P₁ is initial pressure (103 kPa)

P₂ is final pressure (unknown)

T₁ is initial temperature (25°C + 273 = 298K)

T₂ is final temperature (928°C + 273 = 1201K)

From the formula,

103/298 = P₂/1201

P₂ = $\frac{103 * 1201}{298}$

P₂ = 415.11 kPa

415.11 kPa is the pressure of the gas when it temperature reaches 928°C.

Answer 2

Hello!

The pressure of the gas when it's temperature reaches 928 °C is 3823,36 kPa

To solve that we need to apply Gay-Lussac's Law. It states that the pressure of a gas when the volume is left constant (like in the case of a sealed container like an aerosol can) is proportional to temperature. This is the relationship derived from this law that we use to solve this problem:

$P2= \frac{P1}{T1}*T2= \frac{103 kPa}{25}*928=3823,36 kPa$

Have a nice day!