The amino acid for this should be Arginine. I am not entirely sure.
12 moles of water H₂O are produced from the combustion of pentane.
Explanation:
We have the following combustion of pentane (C₅H₁₂):
C₅H₁₂ + 8 O₂ → 5 CO₂ + 6 H₂O
Knowing the chemical reaction we devise the following reasoning:
if 1 moles of pentane C₅H₁₂ produces 6 moles of water H₂O
then 2 moles of pentane C₅H₁₂ produces X moles of water H₂O
X = (2 × 6) / 1 = 12 moles of water H₂O
Learn more about:
combustion of organic compounds
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1. Calculate no. of moles by dividing mass given/molar mass
= 0.250 /283.8
2. Now multiply no. of moles with avogadro's no.
3. The answer indicates no. of total atoms..
4.8A
12/2.5=4.8, the current in this wire should be 4.8A
Answer:
A = 356 cm²
Explanation:
In this case, you need to use the formula to calculate the area of regular solid.
This is the following expression:
S = 2LH + 2LW + 2WH
Where:
L: length
W: Width
H: Height
But we do not know the height of the solid. We should calculate it with the given data first:
1424 = 2*28*H + 2*28*16 + 2*16*H
1424 = 56H + 896 + 32H
1424 - 896 = 88H
H = 528/88
<em>H = 6 cm</em>
Now that we know the height we can calculate the area of the other solid. In the other solid the length has been reduced to half, so I will assume that the Width and height is also reduced to half.
L2 = 14 cm
W2 = 8 cm
H2 = 3 cm
Replacing we have:
S = (2*14*3) + (2*14*8) + (2*8*3)
<u>S = 356 cm²</u>
<u>And this should be the total surface area, assuming the width and height is reduced to half too.</u>
If you don't assume it's reduced to half, then use the original values of Width and Height. Doing so, the Surface would be:
S = (2*14*6) + (2*14*16) + (2*6*16)
S = 808 cm²
