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12345 [234]
2 years ago
11

What is the pH when the hydrogen ion concentration is 1 x 10-3 M?

Chemistry
1 answer:
Fynjy0 [20]2 years ago
6 0

Answer:

e. 3

Explanation:

In order to solve this problem we need to keep in mind the definition of pH:

  • pH = -log[H⁺]

As stated by the problem, the hydrogen ion concentration, [H⁺], is 1x10⁻³ M.

As all required information is available, we now can <u>calculate the pH</u>:

  • pH = -log(1x10⁻³ M)
  • pH = 3

The correct option is thus e.

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Calculate the amount of copper (in moles) in a 45.2 g pure copper sheet
tangare [24]

Answer:

0.712 mol

Explanation:

The easiest way to do this is to use a proportion.

1 mol of copper = 63.5 grams (check this using your periodic table).

x mol of copper = 45.2 grams

1/x = 63.5 / 45.2              Cross multiply

63.5 x = 1 * 45.2              Divide by 63.5

x = 45.2/63.5

x = 0.712 mol                   Answer to 3 sig digs

8 0
3 years ago
Which of the following combinations would produce a neutralization reaction?
tresset_1 [31]

Answer:

it is option b

Explanation:

this is because neutralisation reaction takes place only between a base and an acid.

now, in OPTION A it is a neutral and base

OPTIONB  it is acid and base

OPTION C both are base

OPTION D  IT IS NOT POSSIBLE

7 0
3 years ago
Identify the effect of increasing acidity on the solubility of the given compounds.
Ilia_Sergeevich [38]

All the given compounds are basic on acidifying their solubility increases.

<u>Explanation:</u>

  • C a_{3}\left(P O_{4}\right)_{2} solubility will increase, since it is basic in nature, on acidifying  solubility increases.
  • F e S being basic on acidification, the solubility increases.
  • M g C O_{3} is alkaline in nature, it gets neutralized and there is no increase in acidity.
  • M g B r_{2} is a salt and it shows no effect on acidification.
  • A g I is a salt but insoluble in water and shows no effect on acidification.
  • M g(O H)_{2} is strongly basic in nature, on acidifying the solubility increases.
4 0
3 years ago
How would you seprate a mixture of sand and salt?
lys-0071 [83]
First, you mix the salt and sand with water, so the salt dissolves. Next, you filter the sand out, so you have the slat water and sand separated. Then, you evaporate the water, leaving the salt behind.
3 0
3 years ago
Read 2 more answers
For the reaction 2hno3 + mg(oh)2 → mg(no3)2 + 2h2o, how many moles of magnesium nitrate are produced from 8.00 moles of nitric a
Sladkaya [172]
You would get four moles of magnesium nitrate :) you would have to
“ ?molesmg(oh)2 = 8molmg(no3)2 x molmg(oh)2 / 2molhno3 = 4 moles of magnesium nitrate :))) hopefully this helps! <3
7 0
3 years ago
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