A ball is thrown from the top of a 50-ft building with an upward velocity of 24 ft/s. When will it reach its maximum height? How
1 answer:
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Answer:
q(x)= 2x+5
r(x)=6
b(x)=x+4
Step-by-step explanation:
I have found what is missing in your question: Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x).
First, we have to divide the polynomial by x+4 and remember that is x times 2x.
By multiplying this we are going to get and now we are doing separation of it and getting
and getting
Because 5 is showing x times 5 we are going to multiply (x + 4) with 5 and that is 5x + 20.
Now when we can get more simplified we are having: