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jeka94
3 years ago
15

Simplify the complex fraction .

Mathematics
1 answer:
SpyIntel [72]3 years ago
5 0
N-6/n²+11n+24/n+1/n+3

First, we need to factor the following: 
n² + 11n + 24 → (n + 3)(n + 8) 
n² → n * n 
factor of 24 are:
1 x 24
2 x 12
3 x 8  We will use these factors. 3 + 8 = 11
4 x 6

Division involving fractions results to multiplying the first fraction to the reciprocal of the second fraction. 

n-6/(n+3)(n+8) * n+3 / n+1   → n+3 is in both numerator and denominator. Cancel each other out.

n-6/n+8 * 1/n+1
n-6/(n+8)(n+1) Correct answer is Choice D. 
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How many pieces of gum are in 4 packages of gum?<br> 60<br> 75<br> 90<br> 180
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A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t
MakcuM [25]

Answer:

165.

Step-by-step explanation:

Since repetition isn't allowed, there would be 11 choices for the first donut, (11 - 1) = 10 choices for the second donut, and (11 - 2) = 9 choices for the third donut. If the order in which donuts are placed in the bag matters, there would be 11 \times 10 \times 9 unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type 3 \times 2 \times 1 = 6 times.

For example, if a bag includes donut of type x, y, and z, the count 11 \times 10 \times 9 would include the following 3 \times 2 \times 1 arrangements:

  • xyz.
  • xzy.
  • yxz.
  • yzx.
  • zxy.
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Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count 11 \times 10 \times 9 by 3 \times 2 \times 1 = 6 to find the actual number of donut combinations:

\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of 3 objects from a set of 11 distinct objects:

\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}.

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2 years ago
4x + 5 is greater than 11
erastova [34]

Answer:

if your asking if x is greater than 11 it will be false

Step-by-step explanation:

8 0
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