All categories

4 years ago

Will vote brainliest!! Can someone please help me with the empirical formula of

Chemistry

2 answers:

Rasek [7]4 years ago

5 0

Answer:

The answer is C7H8N4O2.

Same problem as your other question - you rounded in a place where you shouldn't have (see explanation below, exact same process)!

Explanation:

These are percents by mass. Pretend you have a 100g sample. That means you have:

46.66g C

4.48g H

31.10g N

17.76g O

Divide each by molar mass to find the moles of each:

C: 46.66 / 12 = 3.89 mol

H: 4.48 / 1 = 4.48 mol

N: 31.10 / 14 = 2.22 mol

O: 17.76 / 16 = 1.11 mol

Now divide each of these values by the lowest of the three to find the ratio between each element in the compound:

C: 3.89 / 1.11 ≈ 3.5

H: 4.48 / 1.11 ≈ 4

N: 2.22 / 1.11 = 2

O: 1.11 / 1.11 = 1

As with your other question, 3.5 is too different from 3, so you can't round it down. The .5 makes it easy to find the LCD - it's 2. Multiply each of the numbers by 2 to get your final answer:

C: 3.5 x 2 = 7

H: 4 x 2 = 8

N: 2 x 2 = 4

O: 1 x 2 = 2

Again, if you were to take the percent masses of the empirical formula you came up with, you'll see they're quite different from the one the question provided, which is why you can't round in this situation.

Ganezh [65]4 years ago

3 0

Answer:

It’s simple. You’re doing it right, the question is just messed up. If you think about it it’s like H2O

Explanation:

You might be interested in

(a) Write a briefexperimental procedure for the chromic acid test.Include all observations such ascolor change, precipitation, e

mel-nik [20]

Answer:

See explanation

Explanation:

a) -About 1-2 drops of the unknown is dissolved in approximately 1 mL of analytical grade acetone standard solution. The test solution is added and shaken thoroughly. If a positive test is not immediately observed, the set should be allowed to stand for 1-2 minutes. A positive result means the appearance of a green color.

b) The functional groups that can be distinguished by the test are alcohols and aldehydes.

Aldehydes give a positive test to chromic acid but ketones do not.

Primary and secondary alcohols give a positive test to chromic acid but tertiary alcohols do not.

c) Chromic Acid Test involves Cr in the +6 oxidation state. A positive test implies the reduction of orange Cr^6+ to green chromium Cr^3+.

d) The compounds were not shown but this image attached from lumen learning summarizes the reaction mechanism of chromic acid test.

3 0

3 years ago

If an increase in temperature accompanies a reaction what occurred

natita [175]

Answer: A. Energy was absorbed

7 0

4 years ago

Read 2 more answers

Using this equation, m1v2=m2v2 , calculate the diluted molarity of 100 mL of a 0.5 M solution when 50 mL of

geniusboy [140]

The molarity of the diluted solution is 0.33 M

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 0. 5 M

Volume of stock solution (V₁) = 100 mL

Volume of diluted solution (V₂) = 100 + 50 = 150 mL

<h3>Molarity of diluted solution (M₂) =? </h3>

The molarity of the diluted solution can be obtained by using the dilution formula as illustrated below:

0.5 × 100 = M₂ × 150

50 = M₂ × 150

Divide both side by 150

M₂ = 50 / 150

Therefore, the molarity of the diluted solution is 0.33 M

Learn more: brainly.com/question/24625656

8 0

3 years ago

What mass of carbon dioxide is produced from the complete combustion of 6.00×10−3 g of methane?

Crazy boy [7]

The answer for the following problem is explained below.

Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

Explanation:

Given:

mass of methane = 6.00 × 10^-3 grams

$CH_{4}$ + $O_{2}$ → $CO_{2}$ + $H_{2}O$

Firstly balance the following equation:

Before balancing the equation:

$CH_{4} + O_{2}$ → $CO_{2} + H_{2} O$

After balancing the equation:

$CH_{4} + 2O_{2}$ → $CO_{2} + 2 H_{2} O$

where;

$CH_{4}$ represents methane molecule

$O_{2}$ represents oxygen molecule

$CO_{2}$ represents carbon dioxide molecule

$H_{2}O$ represents water molecule

$CH_{4}$ +2 $O_{2}$ → $CO_{2}$ + 2 $H_{2}O$

16 grams of methane → 44 grams of carbon dioxide

6 × 10^-3 grams of methane → ?

= $\frac{44*6.00*10^{-3} }{16}$

= 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.

5 0

3 years ago

Why is conical flask used in the freezing point of naphthalene activity?

SpyIntel [72]

Answer:

D. To ensure the cooling process is not affected by surrounding temperature

Explanation:

The conical flask acts as a temperature jacket.

6 0

3 years ago