Answer:
I believe it's either a or b but I'm pretty sure that it's a
Answer:
0.0018 mol/min is the average rate of carbon dioxide gas production in moles per minute during the 10 minutes.
Explanation:
Pressure of carbon dioxide gas = P = 0.25 atm
Volume of carbon dioxide gas = V = 5.0 L
Moles of carbon dioxide gas = n
Temperature of the carbon dioxide gas,T = 550°C = 550+273 K = 823 K
Using an ideal gas equation :


n = 0.018 mol
In 10 minutes pressure of carbon dioxide gas reached to 0.25 atm
Average rate of production of moles of carbon dioxide gas per minute in duration of 10 minutes:

0.0018 mol/min is the average rate of carbon dioxide gas production in moles per minute during the 10 minutes.
Answer:
At the plate boundary, there would be a divergent boundary where we can see a mid ocean ridge and a gap. We would be able to see the mantle because there would be a fissure from where magma will rise and solidify.
Explanation:
Under the South American plate and African plate, there are currents that cause a divergent boundary. They create this boundary since they pull the tectonic plates apart, causing a mid-ocean ridge with an opening that allows the rising of the magma that was underneath. Once that the magma is out, it solidifies, and the currents will try to create another ridge to repeat the process.
When the plates are apart, the mantle that is beneath is exposed, and we can see the magma.
Answer:
<u>1.4 M</u>
Explanation:
n(HBr)=3.115/81
so, 3.115/81=0.0385mol
according to the reaction, n(HBr)=n(KOH)=0.038 mol
C(KOH)=n/V=0.0385/0.02745
0.0385/0.02745 =1.4 M
in short the answer is 1.4 M (molarity)
Answer:
Mole fraction = 0,0166
Explanation:
Mole fraction is defined as mole of a compound per total moles of the mixture. In the solution, the solute is fructose and the solvent is water. That means you need to find moles of fructose and moles of water.
The molecular mass of fructose is 180,16g/mol and mass of water is 18,02 g/mol. Using these values:
91,7g fructose × (1mol / 180,16g) = <em>0,509 moles of fructose</em>
545g water × (1mol / 18,02g) = <em>30,24 moles of water</em>
Thus, mole fraction of fructose is:

<em>Mole fraction = 0,0166</em>
I hope it helps!