Caculate the kinetic energy in J of an electron moving at 6.00x 10 to the sixth power m/s.

Chemistry

1 answer:

asambeis [7]2 years ago

5 0

Answer:

$1.64x10^-^1^7 J$

Explanation:

Due to you know the velocity of the electron, the only thing that you need to do is used the Newtonian kinetic energy formula. The kinetic energy is defined as the work needed by motion body of a given mass to accelerate from rest to its know velocity:

$KE=1/2mv^2=[kg*(m/s)^2]=[J]$

$m_e_- =9.1093835x10^-^3^1 kg$

$KE=9.11x10^-^3^1 kg*(6.00x10^6 m/s)^2=1.64x10^-^1^7 J$

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