Given:
Side length of square is x = 10 in.
To find:
Area of a square with side length x when x = 10 in.
Check whether the area of a square and the length of its side directly proportional.
Solution:
Area of square is
For x=10, we have
Therefore, the area of square is 100 sq. in. when x=10 in.
For x=1,
For x=2,
Here, .
Since, and ratio of area and sides are not always same, therefore the area of depends on the side but not directly proportional to its side.
Answer: 2(h × W) + 2(h × L) + 2(W × L)
Step-by-step explanation: The width, height, and length of a box can all be different. If they are the same, then the box will become a perfectly square box. The volume, or amount of space inside a box is h × W × L. The outside surface area of a box is 2(h × W) + 2(h × L) + 2(W × L)
Answer:
-6 < y < ∞
Step-by-step explanation:
The range is the value of the output, in this case the value of y
The value is from -6 not including -6 to infinity
-6 < y < ∞
Answer:
x = 37
Step-by-step explanation:
Use the theorem formula
a^2+b^2=c^2
35^2 + 12^2 = c^2
1225 + 144 = c^2
1369 = c^2
divide by square root
c = 37
so x = 37
9514 1404 393
Answer:
4.09 seconds
Step-by-step explanation:
The ball is in the air until h(t) = 0. Solving that equation for t, we have ...
0 = -16t^2 +64t +6
t^2 -4t = 3/8 . . . . . . rearrange, divide by 16
t^2 -4t +4 = 4 3/8 . . . add 4 to complete the square
(t -2)^2 = 4.375 . . . . write as a square
t = 2 +√4.375 . . . . . positive square root, add 2
t ≈ 4.09165
The ball was in the air about 4.09 seconds.