Answer is 10(2k+5)
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Work Shown:
20k+50 = 10*2k + 10*5
20k+50 = 10(2k+5)
Note how we can distribute the 10 back in to check our work
10(2k+5) = 10(2k)+10(5) = 20k+50
so that confirms we have the right answer
Another thing to notice is that 10 is the largest factor that we can pull out of 20k and 50. The value 10 is the GCF (greatest common factor) of 20 and 50.
<span>x − y ≥ 3 ... > stands for above on a graph, and the line under it _ stands for shaded.</span>
It would be B. 28 square yards
Answer:
<h2><em><u>4</u></em></h2>
Step-by-step explanation:
![\sqrt[3]{64}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B64%7D%20)
![= \sqrt[3]{4 \times 4 \times 4}](https://tex.z-dn.net/?f=%20%3D%20%20%5Csqrt%5B3%5D%7B4%20%5Ctimes%204%20%5Ctimes%204%7D%20)
= <em><u>4</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>
Yintercepts are where x=0
set to zero to solve
0^2+4y^2=16
4y^2=16
divide 4
y^2=4
sqrt both sides
y=+/-2
xintercept is where y=0
x^2+4(0)^2=16
x^2+0=16
x^2=16
sdqrtboth sides
x=+/-4
yintercepts are (0,2) and (0,-2)
xintercepts are (4,0) and (-4,0)
