Danny sails a boat downstream. The wind pushes the boat along at 21 km/hr. The current runs downstream at 15 km/hr. What is the
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Tension in the rope due to applied force will be given as
angle of applied force with horizontal is 37 degree
displacement along the floor = 6.1 m
so here we can use the formula of work done
now we can plug in all values above
So here work done to pull is given by 691.8 J
Answer:
x(t) = 0.077cos(6.455t)
Explanation:
If the spring can be stretched 0.2 m by a force of 50 N, then the spring constant is:
k = 50 / 0.2 = 250 N/m
The equation of simple harmonic motion is as the following:
where
We also know that the initial velocity is 0.5 m/s, which is also the maximum speed at the equilibrium:
is the initial phase
Therefore, the position of the mass after t seconds is
x(t) = 0.077cos(6.455t)