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hodyreva [135]
3 years ago
13

Which is the ratio of the number of months that begin with the letter N to the total number of months in a year

Mathematics
2 answers:
kramer3 years ago
5 0

Answer:

Your answer is 1:12 because there's only one month that starts with an N, November, and there's twelve months in total. put that together an your ratio is 1:12.

Also i took this exam on FLVS. 02.01 right?

well anyways hope this helped fellow FLVS student!!!

miss Akunina [59]3 years ago
3 0
1:12. ovembe ris the only month starting with the letter "n" and there are 12 months in a year.
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EleoNora [17]

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Answer:

It's A.

Step-by-step explanation:

Since point C divides in the ratio 1:2, one of the coordinates has to be half of the other coordinate. 3 is half of the coordinate 6, which therefore makes it correct.

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4 years ago
The magic dragon cigarette company claims that their cigarettes contain an average of only 10 mg of tar. a random sample of 100
9966 [12]

Answer:

t=\frac{11.5-10}{\frac{4.5}{\sqrt{100}}}=3.333    

Critical value

The significance is 5% so then \alpha=0.05 and \alpha/2=0.025 then the critical value for this case would be z_{\alpha/2}= 1.64. Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true mean is higher than 10 mg

P value

The p value would be given

p_v =P(z>3.333)=0.000434  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 10 mg

Step-by-step explanation:

Information given

\bar X=11.5 represent the sample mean

\sigma=4.5 represent the population standard deviation

n=100 sample size  

\mu_o =10 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is higher than 10mg, the system of hypothesis would be:  

Null hypothesis:\mu \leq 10  

Alternative hypothesis:\mu > 10  

the statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing we got:

t=\frac{11.5-10}{\frac{4.5}{\sqrt{100}}}=3.333    

Critical value

The significance is 5% so then \alpha=0.05 and \alpha/2=0.025 then the critical value for this case would be z_{\alpha/2}= 1.64. Since the calculated value is higher than the critical value we have enough evidence to reject the null hypothesis and we can conclude that the true mean is higher than 10 mg

P value

The p value would be given

p_v =P(z>3.333)=0.000434  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 10 mg

6 0
3 years ago
HELP PLISSSSSSSS!!!!!!!!!!!<br> solve the right triangle shown in the image
schepotkina [342]

Answer:

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Step-by-step explanation:

4 0
3 years ago
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tatuchka [14]

Answer:

(x,y) \rightarrow ( \frac{1}{4} x, \frac{1}{4} y)

Step-by-step explanation:

Quadrilateral BCDE has coordinates B(-8,4), C(0,4), D(8,8) and E(0,8).

Quadrilateral B'C'D'E' has coordinates B'(-2,1), C'(0,1), D'(2,2) and E'(0,2).

When we analyze the coordinates carefully, we realize that the coordinates of the preimage quadrilateral is multiplied by ¼ to obtain the coordinates of the image triangle.

Therefore the rule of the dilation is

(x,y) \rightarrow ( \frac{1}{4} x, \frac{1}{4} y)

3 0
3 years ago
Read 2 more answers
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