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3 years ago

14

Which expressions are equivalent? Select Equivalent or Not equivalent for each pair of expressions. 3(a−b) and 3a−3b 2a(2+b) and

4ab

2 answers:

Lapatulllka [165]3 years ago

5 0

The first one is <span>Equivalent and the second is nonequivalent</span>

zysi [14]3 years ago

5 0

i just took the test, the first one is equivalent and the second one is not.

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32 ÷ 4 x (16 x 1/2) -2

Anika [276]

32 ÷ 4 x (16 x 1/2) -2

= 32 ÷ 4 × 8 -2

= 8 × 8 - 2 = 64-2

= 62

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME!!!

VladimirAG [237]

Answer:

Part 1) $c=\sqrt{146}\ cm$

Part 2) $c=8\sqrt{2}\ in$

Part 3) The diagonal of rectangle is $d=3\sqrt{29}\ cm$

Part 4) The length of the diagonal of computer monitor is $d=15\ in$

Part 5) The ramp is $10.59\ ft$ long

Part 6) The distance between their houses is $=4\sqrt{2}\ mi$

Part 7) $234.31\ mi$

Part 8) 120 feet of wire is required

Step-by-step explanation:

Part 1) we know that

To find the length of the hypotenuse in a right triangle apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (the greater side)

a and b are the legs

we have

$a=11\ cm\\b=5\ cm$

substitute

$c^2=11^2+5^2$

$c^2=146$

$c=\sqrt{146}\ cm$

Part 2) we know that

To find the length of the hypotenuse in a right triangle apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (the greater side)

a and b are the legs

we have

$a=8\ in\\b=8\ in$

substitute

$c^2=8^2+8^2$

$c^2=128$

$c=\sqrt{128}\ in$

simplify

$c=8\sqrt{2}\ in$

Part 3) we know that

To find the length of the diagonal in a rectangle apply the Pythagorean Theorem

$d^2=b^2+h^2$

where

d is the diagonal of rectangle

b and h are the base and the height of rectangle

we have

$b=15\ cm\\hb=6\ cm$

substitute

$d^2=15^2+6^2$

$d^2=261$

$d=\sqrt{261}\ cm$

simplify

$d=3\sqrt{29}\ cm$

Part 4) we know that

To find the length of the diagonal of a computer monitor apply the Pythagorean Theorem

$d^2=w^2+h^2$

where

d is the diagonal of computer monitor

w and h are the wide and the high of computer monitor

we have

$w=12\ in\\h=9\ in$

substitute

$d^2=12^2+9^2$

$d^2=225$

$d=\sqrt{225}\ in$

simplify

$d=15\ in$

Part 5) we know that

To find out the length of the ramp apply the Pythagorean Theorem

$L^2=x^2+y^2$

where

L is the length of the ramp

x is the horizontal distance of the ramp

y is the vertical distance of the ramp

we have

$x=10\ ft\\y=3.5\ ft$

substitute

$L^2=10^2+3.5y^2$

$L^2=112.25$

$L=10.59\ ft$

Part 6) we know that

To find the distance between their houses apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (distance between their houses)

a and b are the legs

we have

$a=4\ mi\\b=4\ mi$

substitute

$c^2=4^2+4^2$

$c^2=32$

$c=4\sqrt{2}\ mi$

Part 7) we know that

The speed is equal to divide the distance by the time

$speed=distance/time$

so

the distance is equal to multiply the speed by the time

$distance=speed*time$

<em>First train</em>

speed=60 mph

time=3 hours

distance=60(3)=180 miles

<em>Second train</em>

speed=50 mph

time=3 hours

distance=50(3)=150 miles

To find out how far apart are the trains at the end of 3 hours apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (distance between the trains)

a and b are the legs

we have

$a=180\ mi\\b=150\ mi$

substitute

$c^2=180^2+150^2$

$c^2=54,900$

$c=234.31\ mi$

Part 8) we know that

For one tree is needed three wire

To find out the length of one wire apply the Pythagorean Theorem

$c^2=a^2+b^2$

where

c is the hypotenuse (length of one wire)

a and b are the distance above the ground and the distance from the base

we have

$a=3\ ft\\b=4\ ft$

substitute

$c^2=3^2+4^2$

$c^2=25$

$c=5\ ft$

so

For one tree is required ----> (5)3=15 ft

therefore

For 8 trees is required

Multiply by 8

15(8)=120 ft

6 0

3 years ago

The following graph represents the quadratic parent function.<br> TRUE OR FALSE

Alex17521 [72]

Answer:

True

Step-by-step explanation:

the graph makes a loop and both ends go in the same direction

3 0

4 years ago

A rectangle has a length of 5/16 inches and a width of 2 1/5 inches. Find the area of the rectangle.

Ghella [55]

Answer:

Step-by-step explanation:

4 0

3 years ago

One of the legs of a right triangle measures 1 cm and its hypotenuse measures 2 cm.

FromTheMoon [43]

Answer:

1.7 cm

Step-by-step explanation:

The formula to find the hypotenuse: $c^{2} = a^{2} +b^{2}$ . In this case, the hypotenus is given.

1) Substitute the values into the formula.

$2^{2} = 1^{2} +b^{2}$

2) Solve for $b$ .

$4 = 1 + b^{2} \\4 - 1 = b^{2}\\3 = b^{2}\\\sqrt{3} = b\\1.73205 = b$

3) Round the answer to the nearest tenth.

$1.7 = b$

4 0

2 years ago