Answer:
nano3+agcl2
Explanation:
double displacement reaction
Answer:
5.83 mol.
Explanation:
- From the balanced reaction:
<em>2Al + 3Ag₂S → 6Ag + Al₂S₃,</em>
It is clear that 2 mol of Al react with 3 mol of Ag₂S to produce 1 mol of Ag and 1 mol of Al₂S₃.
Al reacts with Ag₂S with (2: 3) molar ratio.
<em>So, 2.27 mol of Al reacts completely with 3.4 mol of Ag₂S with (2: 3) molar ratio.</em>
<em />
- The limiting reactant is Ag₂S.
- The excess "left over" reactant is Al.
The reamining moles of excess reactant "Al" = 8.1 mol - 2.27 mol = 5.83 mol.
First, you want to extract the negative from -log(x).
So now you have log(x) = -2
Now you have to use the property loga(x)=b is the same as x=a^2
So now, it is x = 10^-2. Remember that when there is just a log, it is implied that it is ‘a’ is 10.
Then you evaluate the negative square to 1/10^2
Answer is 1/100
