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Feliz [49]
3 years ago
12

PLEASE HELP!!!! 60 points

Chemistry
2 answers:
Tom [10]3 years ago
8 0

Answer:

d

d.d.d.d.d.d..d.d.d.d.d.d.d.d..d.d.d.d.d.d.d

Explanation:

lina2011 [118]3 years ago
7 0

Answer:

Have a nice Day , I would appreciate it if you could mark my answer brainliest

if 1 teacher cant teach all subjects how come 1 student can learn all subjects ?

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NemiM [27]
 the anwser is genotypes which is a personal characsteristic such as skin color eye or hair color or height
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3 years ago
The charges and sizes of the ions in an ionic compound affect the strength of the electrostatic interaction between the ions and
Citrus2011 [14]

Answer:

NaCl>MgCl2> MgS>KBr

Explanation:

The smaller the cation, the higher the lattice energy of the compound

8 0
3 years ago
Kito puts his spoon into a helping of fresh, hot, mashed potatoes as shown in the figure. Which process takes place when the two
Svet_ta [14]

Answer:

B. is the answer

Explanation:

Energy in form of heat is transferred from the warmer mashed potatoes to the cooler spoon.

7 0
3 years ago
A 0.055 mol sample of formaldehyde vapor, CH2O, was placed in a heated 500 mL vessel and some of it decomposed. The reaction is
Elis [28]

Answer:

Kc for this reaction is 0.06825

Explanation:

Step 1: Data given

Number of moles formaldehyde CH2O = 0.055 moles

Volume = 500 mL = 0.500 L

At equilibrium, the CH2O(g) concentration = 0.051 mol

Step 2: The balanced equation

CH2O  <=>  H2 + CO

Step 3: Calculate the initial concentrations

Concentration = moles / volume

[CH2O] = 0.055 moles . 0.500 L

[CH2O] = 0.11 M

[H2] = 0M

[CO] = 0M

Step 4: The concentration at the equilibrium

[CH2O] = 0.11 - X M = 0.051 M

[H2] = XM

[CO] = XM

[CH2O] = 0.11 - X M = 0.051 M

X = 0.11 - 0.051 = 0.059

[H2] = XM = 0.059 M

[CO] = XM = 0.059 M

Step 5: Calculate Kc

Kc = [H2][CO]/[CHO]

Kc = (0.059 * 0.059) / 0.051

Kc = 0.06825

Kc for this reaction is 0.06825

7 0
3 years ago
What is the total number of atoms in 0.20 mol of propanone, CH3COCH3?
Nutka1998 [239]

Answer:

1.2×10²³ atoms.

Explanation:

Data obtained from the question include:

Mole of propanone = 0.20 mole

Number of atoms of propanone =.?

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.022×10²³ atoms.

This implies that 1 mole of propanone also contains 6.022×10²³ atoms.

Thus, we can obtain the number of atoms in 0.20 mole of propanone as illustrated below:

1 mole of propanone contains 6.022×10²³ atoms.

Therefore, 0.20 mole of propanone will contain = 0.2 × 6.022×10²³ = 1.2×10²³ atoms.

Thus, 0.20 mole of propanone contain

1.2×10²³ atoms.

6 0
3 years ago
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