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Feliz [49]
3 years ago
12

PLEASE HELP!!!! 60 points

Chemistry
2 answers:
Tom [10]3 years ago
8 0

Answer:

d

d.d.d.d.d.d..d.d.d.d.d.d.d.d..d.d.d.d.d.d.d

Explanation:

lina2011 [118]3 years ago
7 0

Answer:

Have a nice Day , I would appreciate it if you could mark my answer brainliest

if 1 teacher cant teach all subjects how come 1 student can learn all subjects ?

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Mghso4.5h2O name and molar mass
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Infer Xenon, a nonreactive gas used in strobe lights, is a poor conductor of heat and electricity. Would you expect xenon to be
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  • Hence it's non metal

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4 0
2 years ago
Why would you need to heat the hydrate up to 250 degrees if water boils at 100 degrees Celsius? Do you think that the boiling po
sergeinik [125]

Explanation:

The pure form of water has a boiling point of 100°C. Boiling point is a physical property of matter and it shows that at such temperature, a liquid substance will change state to vapor.

Pure water is made up of 2 atoms of hydrogen and 1 atom of oxygen. The only intermolecular forces between them is the hydrogen bonds that must be broken for the water to boiling off.

In hydrate, water is present in another form. The water is attached to another compound.

For a pure liquid, the they have reasonably constant boiling point and low boiling range.

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8 0
4 years ago
Express the concentration of a 0.0320 M aqueous solution of fluoride, F−, in mass percentage and in parts per million (ppm). Ass
denis23 [38]

Answer:

607 ppm

Explanation:

In this case we can start with the <u>ppm formula</u>:

ppm=\frac{mg~of~solute}{Litters~of~solution}

If we have a solution of <u>0.0320 M</u>, we can say that in 1 L we have 0.032 mol of F^-, because the molarity formula is:

M=\frac{mol}{L}

In other words:

0.0320~M=\frac{mol}{1~L}

mol=0.032~M*1~L=0.032~mol

1~L~of~Solution=0.0320~mol~of~solute

If we use the <u>atomic mass</u> of F  (19 g/mol) we can convert from mol to g:

0.0320~mol~F^-\frac{19~g~F^-}{1~mol~F^-}~=~0.607~g

Now we can <u>convert from g to mg</u> (1 g= 1000 mg), so:

0.607~g\frac{1000~mg}{1~g}=607~mg

Finally we can <u>divide by 1 L</u> to find the ppm:

ppm=\frac{607~mg}{1~L}=~607~ppm

<u>We will have a concentration of 607 ppm.</u>

I hope it helps!

4 0
4 years ago
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