Based on the incomplete neutralization reaction above, the corresponding salts that each reaction would form are as follows:
1. H2SO4 + 2NH4OH----(NH4)2SO4 with water as a byproduct
2. 2NaOH + H2CO3 ----Na2CO3 with water as a byproduct
3. HNO3 + KOH ----KNO3 with water as a byproduct
The two first ones because it’s always the opposite
1m = 100cm
so 10m = 100*10 = 1000cm or in scientific notation 1.00x10^3 cm
1g = 1/1000kg
1mL = 1/1000L
so 1g/mL = (1/1000)/(1/1000)kg/L
=1kg/L
37.5g/mL = 37.5kg/L or 3.75*10^1 kg/L
Answer:
mass CaI2 = 23.424 Kg
Explanation:
From the periodic table we obtain for CaI2:
⇒ molecular mass CaI2: 40.078 + ((2)(126.90)) = 293.878 g/mol
∴ mol CaI2 = (4.80 E25 units )×(mol/6.022 E23 units) = 79.708 mol CaI2
⇒ mass CaI2 = (79.708 mol CaI2)×(293.878 g/mol) = 23424.43 g
⇒ mass CaI2 = 23.424 Kg
