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3 years ago

14

CaCl2 can be melted to produce calcium metal and give off chlorine gas. The equation for this is CaCl2(l) Ca(s) + Cl2(g). If 277

.45 g CaCl2 were melted, how many grams of Ca(s) would be formed? (

2 answers:

Vikki [24]3 years ago

8 0

Answer:

$m_{Ca}=99.982gCa$

Explanation:

Hello, in this case, considering that the undergoing chemical reaction is:

$CaCl_2(l) \rightarrow Ca(s) + Cl_2(g)$

As we see a one-to-one molar relationship between calcium chloride and calcium, by stoichiometry and the given molar masses, the mass of calcium that would be formed is:

$m_{Ca}=277.45gCaCl_2*\frac{1molCaCl_2}{111gCaCl_2} *\frac{1molCa}{1molCaCl_2} *\frac{40gCa}{1molCa} \\m_{Ca}=99.982gCa$

Best regards.

Bess [88]3 years ago

4 0

Answer:

82g

Explanation:

CaCl2 : Ca 111g : 40g

227.45 : xg

xg= (40×227.5)/111

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The water in a pressure cooker boils at a temperature greater than 100°C because it is under pressure. At this higher temperatur

vazorg [7]

Answer:

the activation energy Ea = 179.176 kJ/mol

it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

Explanation:

From the given information

$T_1 = 100^0 C = 100+273 = 373 \ K \\ \\ T_2 = 113^0 C = 113 + 273 = 386 \ K$

$R_1 = \dfrac{1}{7}$

$R_2 = \dfrac{1}{49}$

Thus; $\dfrac{R_2}{R_1} = 7$

Because at 113.0°C; the rate is 7 time higher than at 100°C

Hence:

$In (7) = \dfrac{Ea}{8.314}( \dfrac{1}{373}- \dfrac{1}{386})$

1.9459 = $\dfrac{Ea}{8.314}* 9.0292 *10^{-5}$

$1.9459*8.314 = Ea * 9.0292*10^{-5}$

$16.1782126= Ea * 9.0292*10^{-5}$

$Ea = \dfrac{16.1782126}{ 9.0292*10^{-5}}$

Ea = 179.176 kJ/mol

Thus; the activation energy Ea = 179.176 kJ/mol

b)

here;

$T_2 = 386 \ K \\ \\T_1 = (89.8 + 273)K = 362.8 \ K$

$In(\dfrac{R_2}{R_1})= \dfrac{Ea}{R}(\dfrac{1}{T_1}- \dfrac{1}{T_2})$

$In(\dfrac{R_2}{R_1})= \dfrac{179.176}{8.314}(\dfrac{1}{362.8}- \dfrac{1}{386})$

$In (\dfrac{R_2}{R_1}) = 0.00357$

$\dfrac{R_2}{R_1}= e^{0.00357}$

$\dfrac{R_2}{R_1}= 1.0035$

where ;

$R_2 = \dfrac{1}7{}$

$R_1 = \dfrac{1}{t}$

Now;

$\dfrac{t}{7}= 1.0035$

t = 7.0245 mins

Therefore; it will take 7.0245 mins for the same food to cook in an open pot of boiling water at an altitude of 10000 feet.

4 0

3 years ago