Question

CaCl2 can be melted to produce calcium metal and give off chlorine gas. The equation for this is CaCl2(l) Ca(s) + Cl2(g). If 277.45 g CaCl2 were melted, how many grams of Ca(s) would be formed? (

Answer 1

Answer:

$m_{Ca}=99.982gCa$

Explanation:

Hello, in this case, considering that the undergoing chemical reaction is:

$CaCl_2(l) \rightarrow Ca(s) + Cl_2(g)$

As we see a one-to-one molar relationship between calcium chloride and calcium, by stoichiometry and the given molar masses, the mass of calcium that would be formed is:

$m_{Ca}=277.45gCaCl_2*\frac{1molCaCl_2}{111gCaCl_2} *\frac{1molCa}{1molCaCl_2} *\frac{40gCa}{1molCa} \\m_{Ca}=99.982gCa$

Best regards.

Answer 2

Answer:

82g

Explanation:

CaCl2 : Ca 111g : 40g

227.45 : xg

xg= (40×227.5)/111