Q4, 4y²=60
y=√15 ( i am not sure)
q6, (5+y) ²=81
5+y=9
y=4
q7 (x+4) (x) =77
x²+4x-77=0
(x+11) (x-7) =0
x=-11(rej) or x=7
therefore ,length= 7+4=11cm
breadth=7cm
As the exercise says, the triangles are similar. So, we can set up proportions between correspondent sides.
In order to solve for x we can set up the proportion between the horizontal and vertical sides:
Solving this proportion for x implies 
Now you can solve for m and p using the pythagorean theorem, because both triangles are right:
Then, we know that the hypothenuse of the big triangle is m+p, so we have
which implies
C!! since the domain is all x values
Answer:
x = 12
y = 6√3
Step-by-step explanation:
✅Apply the intersecting secant theorem to find x. Thus:
6(6 + x) = 7(7 + 8³/7)
Convert the mixed fraction to improper fraction
6(6 + x) = 7(7 + 59/7)
36 + 6x = 49 + 59
36 + 6x = 108
6x = 108 - 36
6x = 72
Divide both sides by 6
x = 72/6
x = 12
✅Apply the tangent-secant theorem to find y. Thus:
y² = 6(6 + x)
Plug in the value of x
y² = 6(6 + 12)
y² = 6(18)
y² = 108
y = √108
y = 6√3
